本文整理了Java中org.locationtech.jts.geom.Geometry.touches()
方法的一些代码示例,展示了Geometry.touches()
的具体用法。这些代码示例主要来源于Github
/Stackoverflow
/Maven
等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。Geometry.touches()
方法的具体详情如下:
包路径:org.locationtech.jts.geom.Geometry
类名称:Geometry
方法名:touches
[英]Tests whether this geometry touches the argument geometry.
The touches
predicate has the following equivalent definitions:
The geometries have at least one point in common, but their interiors do not intersect.
The DE-9IM Intersection Matrix for the two geometries matches at least one of the following patterns
[FT*******]
[F**T*****]
[F***T****]
false
, since points have only interiors. This predicate is symmetric.touches
谓词具有以下等效定义:[FT*******]
[F**T*****]
[F***T****]
如果两个几何图形的尺寸均为0,则谓词将返回false
,因为点只有内部。这个谓词是对称的。
代码示例来源:origin: geotools/geotools
public static boolean touches(Geometry arg0, Geometry arg1) {
if (arg0 == null || arg1 == null) return false;
Geometry _this = arg0;
return _this.touches(arg1);
}
代码示例来源:origin: geotools/geotools
public boolean touches(Geometry g) {
return geometry.touches(g);
}
代码示例来源:origin: geotools/geotools
public boolean evaluateInternal(Geometry left, Geometry right) {
return left.touches(right);
}
代码示例来源:origin: geotools/geotools
@DescribeProcess(
title = "Touches Test",
description =
"Tests if two geometries have at least one boundary point in common, but share no interior points."
)
@DescribeResult(description = "True if the inputs touch")
public static boolean touches(
@DescribeParameter(name = "a", description = "First input geometry") Geometry a,
@DescribeParameter(name = "b", description = "Second input geometry") Geometry b) {
return a.touches(b);
}
代码示例来源:origin: locationtech/jts
/**
* Default implementation.
*/
public boolean touches(Geometry g)
{
return baseGeom.touches(g);
}
代码示例来源:origin: locationtech/geowave
@Override
public boolean apply(Geometry geom1, Geometry geom2) {
return geom1.touches(geom2);
}
}
代码示例来源:origin: orbisgis/h2gis
/**
* Return true if the geometry A touches the geometry B
* @param a Geometry Geometry.
* @param b Geometry instance
* @return true if the geometry A touches the geometry B
*/
public static Boolean geomTouches(Geometry a,Geometry b) {
if(a==null || b==null) {
return null;
}
return a.touches(b);
}
}
代码示例来源:origin: locationtech/jts
public static boolean touches(Geometry a, Geometry b) { return a.touches(b); }
}
代码示例来源:origin: geotools/geotools
Geometry gt2 = (Geometry) tmp2.getDefaultGeometry();
if (gt2.touches(gt)) {
return false;
代码示例来源:origin: geotools/geotools
if (g1.touches(g2) != expected) {
results.error(
f1,
代码示例来源:origin: org.opengeo/geodb
/**
* Returns TRUE if the geometries have at least one point in common, but their interiors do not
* intersect.
*/
public static boolean ST_Touches( byte[] wkb1, byte[] wkb2) {
if ( wkb1 == null || wkb2 == null ) {
return false;
}
Geometry g1 = gFromWKB(wkb1);
Geometry g2 = gFromWKB(wkb2);
return g1.touches( g2 );
}
代码示例来源:origin: jdeolive/geodb
/**
* Returns TRUE if the geometries have at least one point in common, but their interiors do not
* intersect.
*/
public static boolean ST_Touches( byte[] wkb1, byte[] wkb2) {
if ( wkb1 == null || wkb2 == null ) {
return false;
}
Geometry g1 = gFromWKB(wkb1);
Geometry g2 = gFromWKB(wkb2);
return g1.touches( g2 );
}
代码示例来源:origin: geotools/geotools
SimpleFeature f2 = fr2.next();
Geometry g2 = (Geometry) f2.getDefaultGeometry();
if (g1.touches(g2) != expected) {
results.error(
f1,
代码示例来源:origin: locationtech/jts
public void doPredicates(Geometry a, Geometry b) throws Exception
{
assertTrue( a.contains(b) == a.relate(b).isContains() );
assertTrue( a.crosses(b) == a.relate(b).isCrosses(a.getDimension(), b.getDimension()) );
assertTrue( a.disjoint(b) == a.relate(b).isDisjoint() );
assertTrue( a.equals(b) == a.relate(b).isEquals(a.getDimension(), b.getDimension()) );
assertTrue( a.intersects(b) == a.relate(b).isIntersects() );
assertTrue( a.overlaps(b) == a.relate(b).isOverlaps(a.getDimension(), b.getDimension()) );
assertTrue( a.touches(b) == a.relate(b).isTouches(a.getDimension(), b.getDimension()) );
assertTrue( a.within(b) == a.relate(b).isWithin() );
}
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