android.widget.ListView.getTop()方法的使用及代码示例

x33g5p2x  于2022-01-23 转载在 其他  
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本文整理了Java中android.widget.ListView.getTop()方法的一些代码示例,展示了ListView.getTop()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。ListView.getTop()方法的具体详情如下:
包路径:android.widget.ListView
类名称:ListView
方法名:getTop

ListView.getTop介绍

暂无

代码示例

代码示例来源:origin: tianshaojie/AndroidFine

private boolean isFirstItemVisible() {
  final Adapter adapter = mRootView.getAdapter();
  if (null == adapter || adapter.isEmpty()) {
    return true;
  } else {
    /**
     * This check should really just be:
     * mRootView.getFirstVisiblePosition() == 0, but PtRListView
     * internally use a HeaderView which messes the positions up. For
     * now we'll just add one to account for it and rely on the inner
     * condition which checks getTop().
     */
    if (mRootView.getFirstVisiblePosition() <= 1) {
      final View firstVisibleChild = mRootView.getChildAt(0);
      if (firstVisibleChild != null) {
        return firstVisibleChild.getTop() >= mRootView.getTop();
      }
    }
  }
  return false;
}

代码示例来源:origin: stackoverflow.com

int t = view.getTop() + listView.getTop();
int l = view.getLeft() + listView.getLeft();

代码示例来源:origin: stackoverflow.com

int t = view.getTop() + listView.getTop();
int l = view.getLeft() + listView.getLeft();

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