BST二叉搜索树查找节点元素,binarytree,Python
import random
import binarytree
def app():
t = binarytree.bst(height=5, is_perfect=False)
print(t)
print('-----')
idx = random.randint(1, t.size - 1)
target = t.levelorder[idx].value # 从节点中随机找一个值
print('查找', target)
path = search(t, target)
print('路线', path)
def search(node, target):
path = []
while True:
path.append(node)
if node.value == target:
break
if node is not None:
if target > node.value:
node = node.right
else:
node = node.left
return path
if __name__ == '__main__':
app()
运行日志输出:
__2__________________________________
/ \
0 ___________________60___
\ / \
1 _________36______ _62
/ \ /
4___ ____39___ 61
/ \ / \
3 _31 37 _45
/ \ \ / \
23 33 38 43 49
-----
查找 45
路线 [Node(2), Node(60), Node(36), Node(39), Node(45)]
版权说明 : 本文为转载文章, 版权归原作者所有 版权申明
原文链接 : https://zhangphil.blog.csdn.net/article/details/121636492
内容来源于网络,如有侵权,请联系作者删除!