本文整理了Java中gov.sandia.cognition.math.matrix.Vector.isSparse()方法的一些代码示例，展示了Vector.isSparse()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台，是从一些精选项目中提取出来的代码，具有较强的参考意义，能在一定程度帮忙到你。Vector.isSparse()方法的具体详情如下：
包路径：gov.sandia.cognition.math.matrix.Vector
类名称：Vector
方法名：isSparse

Vector.isSparse介绍

[英]Returns true if this vector has a potentially sparse underlying structure. This can indicate that it is faster to only process the non-zero elements rather than to do dense operations on it. Of course, even with a sparse structure, there may be no zero elements or conversely even with a non-sparse (dense) structure there may be many zero elements.
[中]如果此向量具有潜在的稀疏底层结构，则返回true。这表明只处理非零元素比对其进行密集操作更快。当然，即使是稀疏结构，也可能没有零元素，反之，即使是非稀疏（密集）结构，也可能有许多零元素。

代码示例

代码示例来源：origin: algorithmfoundry/Foundry

final int columnCount = other.getDimensionality();
final Matrix result;
if (!other.isSparse())

代码示例来源：origin: gov.sandia.foundry/gov-sandia-cognition-common-core

final int columnCount = other.getDimensionality();
final Matrix result;
if (!other.isSparse())

代码示例来源：origin: algorithmfoundry/Foundry

final int columnCount = other.getDimensionality();
final Matrix result;
if (!other.isSparse())