org.apache.poi.xwpf.converter.core.openxmlformats.ZipArchive.hasEntry()方法的使用及代码示例

x33g5p2x  于2022-02-05 转载在 其他  
字(1.4k)|赞(0)|评价(0)|浏览(161)

本文整理了Java中org.apache.poi.xwpf.converter.core.openxmlformats.ZipArchive.hasEntry()方法的一些代码示例,展示了ZipArchive.hasEntry()的具体用法。这些代码示例主要来源于Github/Stackoverflow/Maven等平台,是从一些精选项目中提取出来的代码,具有较强的参考意义,能在一定程度帮忙到你。ZipArchive.hasEntry()方法的具体详情如下:
包路径:org.apache.poi.xwpf.converter.core.openxmlformats.ZipArchive
类名称:ZipArchive
方法名:hasEntry

ZipArchive.hasEntry介绍

[英]Returns true if ZipArchive contains an entry with the given name.
[中]如果ZipArchive包含具有给定名称的条目,则返回true。

代码示例

代码示例来源:origin: fr.opensagres.xdocreport/org.apache.poi.xwpf.converter.core-gae

/**
 * Write the given entry from the document archive in the given output stream.
 * 
 * @param archive
 * @param outputStream
 * @throws IOException
 */
public static void writeEntry( ZipArchive archive, String entryName, OutputStream outputStream )
  throws IOException
{
  if ( !archive.hasEntry( entryName ) )
  {
    throw new IOException( "Cannot find entry name=" + entryName + " in the document archive." );
  }
  outputStream.write( archive.cacheEntries.get( entryName ) );
}

代码示例来源:origin: fr.opensagres.xdocreport/org.apache.poi.xwpf.converter.core

/**
 * Write the given entry from the document archive in the given output stream.
 * 
 * @param archive
 * @param outputStream
 * @throws IOException
 */
public static void writeEntry( ZipArchive archive, String entryName, OutputStream outputStream )
  throws IOException
{
  if ( !archive.hasEntry( entryName ) )
  {
    throw new IOException( "Cannot find entry name=" + entryName + " in the document archive." );
  }
  outputStream.write( archive.cacheEntries.get( entryName ) );
}

相关文章