databricks和spark中的公共表表达式(cte)

cuxqih21 于 2021-05-29 发布在 Spark

关注(0)|答案(1)|浏览(703)

我在databricks中有一个sparkDataframe。我正在尝试用公共表表达式（cte）运行一些sql查询。以下是前10行数据

+----------+----------+------+---+---+---------+-----------------+
| data_date|   user_id|region|sex|age|age_group|sum(duration_min)|
+----------+----------+------+---+---+---------+-----------------+
|2020-01-01|22600560aa|     1|  1| 28|        2|              0.0|
|2020-01-01|17148900ab|     6|  2| 60|        5|           1138.0|
|2020-01-01|21900230aa|     5|  1| 43|        4|              0.0|
|2020-01-01|35900050ac|     8|  1| 16|        1|            224.0|
|2020-01-01|22300280ad|     6|  2| 44|        4|              8.0|
|2020-01-02|19702160ac|     2|  2| 55|        5|              0.0|
|2020-02-02|17900020aa|     5|  2| 64|        5|            264.0|
|2020-02-02|16900120aa|     3|  1| 69|        6|              0.0|
|2020-02-02|11160900aa|     6|  2| 52|        5|              0.0|
|2020-03-02|16900290aa|     5|  1| 37|        3|              0.0|
+----------+----------+------+---+---+---------+-----------------+

在这里，我将每个用户的注册日期存储在regs cte中，然后计算每个月的注册数。这个带有cte的块在databricks中没有任何问题

%sql

    WITH regs AS (
      SELECT
        user_id,
        MIN(data_date) AS reg_date
      FROM df2
      GROUP BY user_id)

    SELECT
      month(reg_date)  AS reg_month,
      COUNT(DISTINCT user_id) AS users
    FROM regs
    GROUP BY reg_month
    ORDER BY reg_month ASC;

但是，当我将另一个cte添加到以前的sql查询中时，它返回一个错误（我在sqlserver中测试了这个块，它工作正常）。我不明白为什么他不在spark databricks工作。

%sql

WITH regs AS (
  SELECT
    user_id,
    MIN(data_date) AS reg_date
  FROM df2
  GROUP BY user_id
  ),

  regs_per_month AS (
    SELECT
      month(reg_date) AS reg_month,
      COUNT(DISTINCT user_id) AS users
    FROM regs
    GROUP BY reg_month
  )

SELECT
  reg_month,
  users,
  LAG(users, 1) OVER (ORDER BY regs_per_month ASC) AS previous_users
FROM regs_per_month
ORDER BY reg_month ASC;

这是错误信息

Error in SQL statement: AnalysisException: cannot resolve '`regs_per_month`' given input columns: [regs_per_month.reg_month, regs_per_month.users]; line 20 pos 31;
'Sort ['reg_month ASC NULLS FIRST], true

apache-spark apache-spark-sql databricks common-table-expression

来源：https://stackoverflow.com/questions/62533277/common-table-expressions-ctes-in-databricks-and-spark

1条答案

按热度按时间

tez616oj1#

只需使用逗号，就可以在sparksql中嵌套公共表表达式（cte）

%sql
;WITH regs AS (
SELECT
  user_id,
  MIN(data_date) AS reg_date
FROM df2
GROUP BY user_id
),
regs_per_month AS (
SELECT
  month(reg_date) AS reg_month,
  COUNT(DISTINCT user_id) AS users
FROM regs
GROUP BY reg_month
)
SELECT
  reg_month,
  users,
  LAG(users, 1) OVER (ORDER BY reg_month ASC) AS previous_users
FROM regs_per_month
ORDER BY reg_month ASC;

我的结果：

如前所述 LAG 语句应引用 reg_month 列而不是 regs_per_month cte公司。
作为嵌套CTE的另一种方法，您可以使用多个， WITH 陈述，例如

%sql
;WITH regs_per_month AS ( 
  WITH regs AS ( 
  SELECT
    user_id,
    MIN(data_date) AS reg_date
  FROM df2
  GROUP BY user_id
  )
  SELECT 
    month(reg_date) AS reg_month,
    COUNT(DISTINCT user_id) AS users
  FROM regs
  GROUP BY reg_month
)
SELECT 
  reg_month, 
  users,
  LAG( users, 1 ) OVER ( ORDER BY reg_month ASC ) AS previous_users
FROM regs_per_month
ORDER BY reg_month ASC;

赞(0）回复(0）举报 2021-05-29

我来回答

databricks和spark中的公共表表达式(cte)

1条答案

相关问题

热门标签

最新问答