您可以使用posexplode（）自定义项来完成。

WITH
data AS (
  SELECT 1 AS id, 5 AS value, 1 AS start, 4 AS `end`
  UNION ALL
  SELECT 2 AS id, 8 AS value, 5 AS start, 9 AS `end`
)
SELECT distinct id, value, (zr.start+rge.diff) as `current`
   FROM data zr LATERAL VIEW posexplode(split(space(zr.`end`-zr.start),' ')) rge as diff, x

下面是它的输出：

+-----+--------+----------+--+
| id  | value  | current  |
+-----+--------+----------+--+
| 1   | 5      | 1        |
| 1   | 5      | 2        |
| 1   | 5      | 3        |
| 1   | 5      | 4        |
| 2   | 8      | 5        |
| 2   | 8      | 6        |
| 2   | 8      | 7        |
| 2   | 8      | 8        |
| 2   | 8      | 9        |
+-----+--------+----------+--+

这可以通过一个递归的公共表表达式来实现，而hive不支持这个表达式。
一种方法是创建一个数字表，并使用它在开始和结束之间生成行。

create table numbers
location 'hdfs_location' as 
select row_number() over(order by somecolumn) as num
from some_table --this can be any table with the desired number of rows 
;

--Join it with the existing table 
select t.id,t.value,n.num as current
from tbl t
join numbers n on n.num>=t.start and n.num<=t.end