您可以更改字符串数组col1的数据类型，而不是int数组，然后您就可以获得col1的数据。
col1数据类型为数组（字符串）时：-

hive>create table base(col1 array<string>,col2 array<string>) row format delimited fields terminated by '\t' collection items terminated by ',';
hive>select * from base;
+--------------+------------------------+--+
|     col1     |          col2          |
+--------------+------------------------+--+
| ["[1","2]"]  | ["['a'","'b'","'c']"]  |
| ["[3","4]"]  | ["['d'","'e'","'f']"]  |
+--------------+------------------------+--+

为什么会出现这种行为，是因为hive无法将数组中的值检测为整数，因为我们有1,2个值包含在[]col1中elements:-

hive>select col1[0],col1[1] from base;
    +------+------+--+
    | _c0  | _c1  |
    +------+------+--+
    | [1   | 2]   |
    | [3   | 4]   |
    +------+------+--+

（或）
col1数据类型作为数组（int类型）：-
如果您不想更改数据类型，那么您需要将输入文件保持如下，不使用[]方括号表示数组（即col1）值。

1,2     ['a','b','c']
3,4     ['d','e','f']

然后创建与问题中提到的相同的表，然后hive可以将前1,2作为数组元素检测为int类型。

hive> create table base(col1 array<int>,col2 array<string>) row format delimited fields terminated by '\t' collection items terminated by ',';

hive> select * from base;
+--------+------------------------+--+
|  col1  |          col2          |
+--------+------------------------+--+
| [1,2]  | ["['a'","'b'","'c']"]  |
| [3,4]  | ["['d'","'e'","'f']"]  |
+--------+------------------------+--+

访问数组elements:-

hive> select col1[0] from base;
    +------+--+
    | _c0  |
    +------+--+
    | 1    |
    | 3    |
    +------+--+