如果我有表格的输入( (0, 1), A 0 0.0), ((0, 2), A 0 0.0), ((0, 0), A 0 0.0) 哪里 (0,1) , (0,2), (0,0) 是键，如何将它们分隔为多个键值对。
例如，如果我想打印键，上面的值应该返回：

(0,1) , A 0 0 0.0
(0,2) , A 0 0 0.0
(0,0) , A 0 0 0.0

此输出将用于my reducer函数，其代码为：

import sys
import string
import numpy
import re

# number of columns of A/rows of B

n = int(sys.argv[1])

# Create data structures to hold the current row/column values (if needed; your code goes here)

currentkey = None

# input comes from STDIN (stream data that goes to the program)

for line in sys.stdin:
    #print(line)
    #Remove leading and trailing whitespace
    #line = line.strip().replace("(","").replace(")","")
    #re.sub(r"[\(\[].*?[\)\]]", "", line)
    #line = line.strip().translate(None, "()")
    line = line.strip()

    #''.join(line.translate(string.maketrans("()[]"," "*4)).split(' ')[::2])
    print(line)

    #print(line.__class__)

    #Get key/value
    key, value = line.split('\t',1)

    print ("key: " + str(key))
    print ("Value: " + str(value))
    #Parse key/value input (your code goes here)
    # for val in value:
    #   if val[0] == "A":
    #       list_a.append(val)
    #       print(list_a)
    #
    #
    #   else:
    #       list_b.append(val)
    #       print(list_b)

    #If we are still on the same key...
    if key==currentkey:

        #Process key/value pair (your code goes here)
        for a in list_a:
            #remove first two elems so that we're left with value
            a = a[2:]
        print(list_a)
        result_a = list(map(int,result_a))
        for b in list_b:
            b = b[2:]
        print(list_b)
        result_b = list(map(int, result_b))
        #multiply result_a and result_b for current key
        result_ab = [a*b for a,b in zip(result_a,result_b)]
        finalResult = sum(result_ab)