仅返回chararray中的第一项

voase2hg  于 2021-06-02  发布在  Hadoop
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我有以下数据(加载在变量a中):

(a1:a2:a3|a4:a5:a6)
(b1:b2:b3)
(c1:c2:c3|c4:c5:c6|c7:c8:c9)

我希望我的最终输出如下:

(a1:a2:a3)
(a4:a5:a6)
(b1:b2:b3)
(c1:c2:c3)
(c4:c5:c6)
(c7:c8:c9)

以下是我所做的:

B = foreach B generate flatten(STRSPLIT($0, '\\|')) as splitted:chararray;

这将数据转换为:

(a1:a2:a3,a4:a5:a6)
(b1:b2:b3)
(c1:c2:c3,c4:c5:c6,c7:c8:c9)

具有以下结构:

B: {splitted: chararray}

然而,当我试图将这个字符展平为单独的元组时,它只会吐出第一项。我尝试了几种不同的方法来获得我想要的输出,但我总是得到第一项。以下是我尝试过的几件事:

req_output = foreach B generate flatten(STRSPLIT(splitted, ','));

req_output = foreach B generate flatten(TOBAG(*));

在这两种情况下,我得到以下输出:

(a1:a2:a3)
(b1:b2:b3)
(c1:c2:c3)

我不知道为什么会这样。如何将所有项作为不同的元组?我没有太多的经验,所以在Pig,任何帮助将不胜感激。

rqqzpn5f

rqqzpn5f1#

relation B 您只存储第一项(即 splitted variable ),这就是这个问题的原因。你能去掉这个变量吗 splitted 从关系b?

B = foreach B generate flatten(STRSPLIT($0, '\\|')) as splitted:chararray;

B = foreach B generate flatten(STRSPLIT($0, '\\|'));

你可以用两种方法来解决这个问题。
输入:

a1:a2:a3|a4:a5:a6
b1:b2:b3
c1:c2:c3|c4:c5:c6|c7:c8:c9

选项1:使用标记化

A = LOAD 'input' USING PigStorage() AS(line:chararray);
B = FOREACH A GENERATE FLATTEN(TOKENIZE(line,'\\|'));
DUMP B;

选项2:使用strsplit+tobag

A = LOAD 'input' USING PigStorage() AS(line:chararray);
B = FOREACH A GENERATE FLATTEN(STRSPLIT(line,'\\|'));
C = FOREACH B GENERATE FLATTEN(TOBAG(*));
DUMP C;

选项3:使用strsplittobag(仅限pig版本0.14)

A = LOAD 'input' USING PigStorage() AS(line:chararray);
B = FOREACH A GENERATE FLATTEN(STRSPLITTOBAG(line,'\\|'));
DUMP B;

输出:

(a1:a2:a3)
(a4:a5:a6)
(b1:b2:b3)
(c1:c2:c3)
(c4:c5:c6)
(c7:c8:c9)

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