我需要把两个mapreduce工作链起来。我使用jobcontrol将job2设置为job1的依赖项。它工作,输出文件被创建!!但它不会停止!在壳中它保持这种状态:
12/09/11 19:06:24 WARN mapred.JobClient: Use GenericOptionsParser for parsing the arguments. Applications should implement Tool for the same.
12/09/11 19:06:25 INFO input.FileInputFormat: Total input paths to process : 1
12/09/11 19:06:25 INFO util.NativeCodeLoader: Loaded the native-hadoop library
12/09/11 19:06:25 WARN snappy.LoadSnappy: Snappy native library not loaded
12/09/11 19:07:00 WARN mapred.JobClient: Use GenericOptionsParser for parsing the arguments. Applications should implement Tool for the same.
12/09/11 19:07:00 INFO input.FileInputFormat: Total input paths to process : 1
我怎样才能阻止它?这是我的主要任务。
public static void main(String[] args) throws Exception {
Configuration conf = new Configuration();
Configuration conf2 = new Configuration();
Job job1 = new Job(conf, "canzoni");
job1.setJarByClass(CanzoniOrdinate.class);
job1.setMapperClass(CanzoniMapper.class);
job1.setReducerClass(CanzoniReducer.class);
job1.setOutputKeyClass(Text.class);
job1.setOutputValueClass(IntWritable.class);
ControlledJob cJob1 = new ControlledJob(conf);
cJob1.setJob(job1);
FileInputFormat.addInputPath(job1, new Path(args[0]));
FileOutputFormat.setOutputPath(job1, new Path("/user/hduser/tmp"));
Job job2 = new Job(conf2, "songsort");
job2.setJarByClass(CanzoniOrdinate.class);
job2.setMapperClass(CanzoniSorterMapper.class);
job2.setSortComparatorClass(ReverseOrder.class);
job2.setInputFormatClass(KeyValueTextInputFormat.class);
job2.setReducerClass(CanzoniSorterReducer.class);
job2.setMapOutputKeyClass(IntWritable.class);
job2.setMapOutputValueClass(Text.class);
job2.setOutputKeyClass(Text.class);
job2.setOutputValueClass(IntWritable.class);
ControlledJob cJob2 = new ControlledJob(conf2);
cJob2.setJob(job2);
FileInputFormat.addInputPath(job2, new Path("/user/hduser/tmp/part*"));
FileOutputFormat.setOutputPath(job2, new Path(args[1]));
JobControl jobctrl = new JobControl("jobctrl");
jobctrl.addJob(cJob1);
jobctrl.addJob(cJob2);
cJob2.addDependingJob(cJob1);
jobctrl.run();
////////////////
// NEW CODE ///
//////////////
// delete jobctrl.run();
Thread t = new Thread(jobctrl);
t.start();
String oldStatusJ1 = null;
String oldStatusJ2 = null;
while (!jobctrl.allFinished()) {
String status =cJob1.toString();
String status2 =cJob2.toString();
if (!status.equals(oldStatusJ1)) {
System.out.println(status);
oldStatusJ1 = status;
}
if (!status2.equals(oldStatusJ2)) {
System.out.println(status2);
oldStatusJ2 = status2;
}
}
System.exit(0);
} }
4条答案
按热度按时间6ojccjat1#
我基本上做了彼得罗上面提到的。
在我的map/reduce课程中我有:
其中我只传递jobcontrol对象。
cmssoen22#
试试这个:
wr98u20j3#
只是对sinemetu1共享的代码片段进行了调整。。
当jobcontrol本身实现runnable时,可以放弃对jobrunner的调用
我还偶然发现了这个链接,其中用户确认jobcontrol只能使用新线程运行。https://www.mail-archive.com/common-user@hadoop.apache.org/msg00556.html
vwkv1x7d4#
jobcontrol对象本身是可运行的,因此您可以这样使用它: