链作业-作业控制不停止

jljoyd4f  于 2021-06-03  发布在  Hadoop
关注(0)|答案(4)|浏览(442)

我需要把两个mapreduce工作链起来。我使用jobcontrol将job2设置为job1的依赖项。它工作,输出文件被创建!!但它不会停止!在壳中它保持这种状态:

12/09/11 19:06:24 WARN mapred.JobClient: Use GenericOptionsParser for parsing the arguments. Applications should implement Tool for the same.
12/09/11 19:06:25 INFO input.FileInputFormat: Total input paths to process : 1
12/09/11 19:06:25 INFO util.NativeCodeLoader: Loaded the native-hadoop library
12/09/11 19:06:25 WARN snappy.LoadSnappy: Snappy native library not loaded
12/09/11 19:07:00 WARN mapred.JobClient: Use GenericOptionsParser for parsing the arguments. Applications should implement Tool for the same.
12/09/11 19:07:00 INFO input.FileInputFormat: Total input paths to process : 1

我怎样才能阻止它?这是我的主要任务。

public static void main(String[] args) throws Exception {
    Configuration conf = new Configuration();
    Configuration conf2 = new Configuration();

    Job job1 = new Job(conf, "canzoni");
    job1.setJarByClass(CanzoniOrdinate.class);
    job1.setMapperClass(CanzoniMapper.class);
    job1.setReducerClass(CanzoniReducer.class);
    job1.setOutputKeyClass(Text.class);
    job1.setOutputValueClass(IntWritable.class);

    ControlledJob cJob1 = new ControlledJob(conf);
    cJob1.setJob(job1);
    FileInputFormat.addInputPath(job1, new Path(args[0]));
    FileOutputFormat.setOutputPath(job1, new Path("/user/hduser/tmp"));

    Job job2 = new Job(conf2, "songsort");
    job2.setJarByClass(CanzoniOrdinate.class);
    job2.setMapperClass(CanzoniSorterMapper.class);
    job2.setSortComparatorClass(ReverseOrder.class);
    job2.setInputFormatClass(KeyValueTextInputFormat.class);
    job2.setReducerClass(CanzoniSorterReducer.class);
    job2.setMapOutputKeyClass(IntWritable.class);
    job2.setMapOutputValueClass(Text.class);
    job2.setOutputKeyClass(Text.class);
    job2.setOutputValueClass(IntWritable.class);

    ControlledJob cJob2 = new ControlledJob(conf2);
    cJob2.setJob(job2);
    FileInputFormat.addInputPath(job2, new Path("/user/hduser/tmp/part*"));
    FileOutputFormat.setOutputPath(job2, new Path(args[1]));

    JobControl jobctrl = new JobControl("jobctrl");
    jobctrl.addJob(cJob1);
    jobctrl.addJob(cJob2);
    cJob2.addDependingJob(cJob1);
    jobctrl.run();

    ////////////////
    // NEW CODE ///   
    //////////////

    // delete jobctrl.run();
    Thread t = new Thread(jobctrl);
    t.start();
    String oldStatusJ1 = null;
    String oldStatusJ2 = null;
    while (!jobctrl.allFinished()) {
      String status =cJob1.toString();
      String status2 =cJob2.toString();
      if (!status.equals(oldStatusJ1)) {
        System.out.println(status);
        oldStatusJ1 = status;
      }
      if (!status2.equals(oldStatusJ2)) {
        System.out.println(status2);
        oldStatusJ2 = status2;
      }     
     }
    System.exit(0);

} }

6ojccjat

6ojccjat1#

我基本上做了彼得罗上面提到的。

public class JobRunner implements Runnable {
  private JobControl control;

  public JobRunner(JobControl _control) {
    this.control = _control;
  }

  public void run() {
    this.control.run();
  }
}

在我的map/reduce课程中我有:

public void handleRun(JobControl control) throws InterruptedException {
    JobRunner runner = new JobRunner(control);
    Thread t = new Thread(runner);
    t.start();

    while (!control.allFinished()) {
        System.out.println("Still running...");
        Thread.sleep(5000);
    }
}

其中我只传递jobcontrol对象。

cmssoen2

cmssoen22#

试试这个:

Thread jcThread = new Thread(jobControl);
    jcThread.start();
    System.out.println("循环判断jobControl运行状态 >>>>>>>>>>>>>>>>");
    while (true) {
        if (jobControl.allFinished()) {
        System.out.println("====>> jobControl.allFinished=" + jobControl.getSuccessfulJobList());
        jobControl.stop();
        // 如果不加 break 或者 return,程序会一直循环
        break;
    }

    if (jobControl.getFailedJobList().size() > 0) {
        succ = 0;
        System.out.println("====>> jobControl.getFailedJobList=" + jobControl.getFailedJobList());
        jobControl.stop();

        // 如果不加 break 或者 return,程序会一直循环
        break;
    }
}
wr98u20j

wr98u20j3#

只是对sinemetu1共享的代码片段进行了调整。。
当jobcontrol本身实现runnable时,可以放弃对jobrunner的调用

Thread thread = new Thread(jobControl);
        thread.start();

        while (!jobControl.allFinished()) {
            System.out.println("Still running...");
            Thread.sleep(5000);
        }

我还偶然发现了这个链接,其中用户确认jobcontrol只能使用新线程运行。https://www.mail-archive.com/common-user@hadoop.apache.org/msg00556.html

vwkv1x7d

vwkv1x7d4#

jobcontrol对象本身是可运行的,因此您可以这样使用它:

new Thread(myJobControlInstance).start()

相关问题