semanticexception[error 10007]:不明确的列引用\u c1

lxkprmvk  于 2021-06-04  发布在  Hadoop
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在配置单元查询中使用四级嵌套时,我遇到了一个问题。下面是我正在执行的查询-

SELECT *, 
SUM(qtod.amount) OVER (PARTITION BY qtod.id, qtod.year_begin_date ORDER BY qtod.tran_date)
FROM (SELECT *, 
    SUM(mtod.amount) OVER (PARTITION BY mtod.id, mtod.quarter_begin_date ORDER BY mtod.tran_date)
    FROM (SELECT *, 
        SUM(wtod.amount) OVER (PARTITION BY wtod.id, wtod.month_begin_date ORDER BY wtod.tran_date)
        FROM (select id,
            year_begin_date,
            quarter_begin_date,
            month_begin_date,
            week_begin_date,
            tran_date,
            amount,
            SUM(amount) 
OVER (PARTITION BY id,week_begin_date ORDER BY tran_date) FROM table_name)wtod)mtod)qtod;

如果我排除第四级嵌套,它工作得很好,但在包含它的同时,会低于error msg-
失败:semanticexception[错误10007]:qtod中的列引用不明确\u c1
为了避免筑巢,我尝试了另一种方法

SELECT * FROM
    (SELECT id,year_begin_date,tran_date,amount,SUM(amount) OVER (PARTITION BY id,year_begin_date ORDER BY tran_date) FROM yeartodate)ytod
    JOIN 
(SELECT *, SUM(mtod.amount) OVER (PARTITION BY mtod.id, mtod.quarter_begin_date ORDER BY mtod.tran_date)
FROM (SELECT *, SUM(wtod.amount) OVER (PARTITION BY wtod.id, wtod.month_begin_date ORDER BY wtod.tran_date)
FROM (select id,
    year_begin_date,
    quarter_begin_date,
    month_begin_date,
    week_begin_date,
    tran_date,
    amount,
    SUM(amount) 
OVER (PARTITION BY id,week_begin_date ORDER BY tran_date) FROM table_name)wtod)mtod)qtod
ON qtod.id=ytod.id AND qtod.tran_date=ytod.tran_date;

还是有同样的错误。
在网上搜索后,我发现这是一个与Hive本身的问题,根据吉拉提出的Hive
由于jira现在已经修复,并且补丁程序在hive14中可用,所以我尝试在hive14(hdp)上运行它。
还是有同样的错误。
请写下你的建议。。。。。

w46czmvw

w46czmvw1#

函数中的非别名函数调用 SELECT Map到列名 _c1 , _c2 在这种情况下,每个 SELECT ,所以它们都创建一个列 _c1 .
问题是因为你在做 SELECT * 从下一个子查询向下,然后附加另一个Map到 _c1 然后,同一列被命名了两次,因此在不明确的列引用周围出现了一个错误。
解决方案应该是对所有函数调用使用别名,这样它们就不会使用 _c1 默认名称,如下所示:

SELECT * FROM
    (SELECT id,year_begin_date,tran_date,amount,SUM(amount) AS ytod_amount_sum OVER (PARTITION BY id,year_begin_date ORDER BY tran_date) FROM yeartodate)ytod
    JOIN 
(SELECT *, SUM(mtod.amount) AS mtod_amount_sum OVER (PARTITION BY mtod.id, mtod.quarter_begin_date ORDER BY mtod.tran_date)
FROM (SELECT *, SUM(wtod.amount) AS wtod_amount_sum OVER (PARTITION BY wtod.id, wtod.month_begin_date ORDER BY wtod.tran_date)
FROM (select id,
    year_begin_date,
    quarter_begin_date,
    month_begin_date,
    week_begin_date,
    tran_date,
    amount,
    SUM(amount) AS amount_sum
OVER (PARTITION BY id,week_begin_date ORDER BY tran_date) FROM table_name)wtod)mtod)qtod
ON qtod.id=ytod.id AND qtod.tran_date=ytod.tran_date;

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