嘿，所以我在尝试Kafka流和mpReact式消息传递，从Kafka主题中读取内容，然后再返回给它。
Kafka流错误-

org.apache.kafka.streams.errors.StreamsException: Deserialization exception handler is set to fail upon a deserialization error. If you would rather have the streaming pipeline continue after a deserialization error, please set the default.deserialization.exception.handler appropriately.

React式消息传递错误与此类似，但消息传递反序列化到的pojo基本上如下所示-

public class FinancialMessage {

    public String user_id;
    public String stock_symbol;
    public String exchange_id;
    public String trade_type;
    public String date_created;
    public String date_submitted;
    public int quantity;
    public double stock_price;
    public double total_cost;
    public int institution_id;
    public int country_id;
    public boolean compliance_services;
    public boolean technical_validation;
    public boolean schema_validation;
    public boolean business_validation;
    public boolean trade_enrichment;
   }

注意，有一个默认的空构造函数和一个包含所有字段的构造函数。

import java.time.Instant;

import javax.enterprise.context.ApplicationScoped;
import javax.enterprise.inject.Produces;

import org.apache.kafka.common.serialization.Serdes;
import org.apache.kafka.streams.StreamsBuilder;
import org.apache.kafka.streams.Topology;
import org.apache.kafka.streams.kstream.Consumed;
import org.apache.kafka.streams.kstream.GlobalKTable;
import org.apache.kafka.streams.kstream.Materialized;
import org.apache.kafka.streams.kstream.Produced;
import org.apache.kafka.streams.state.KeyValueBytesStoreSupplier;
import org.apache.kafka.streams.state.Stores;

import io.quarkus.kafka.client.serialization.JsonbSerde;
import io.quarkus.kafka.client.serialization.JsonbSerializer;

@ApplicationScoped
public class ComplianceTopology {

    private static final String KTABLE_TOPIC = "kstreams-ktable-topic";
    private static final String INCOMING_TOPIC = "kstreams-incoming-test";
    private static final String OUTGOING_TOPIC = "kstreams-outgoing-test";

    @Produces
    public Topology buildTopology() {

        StreamsBuilder builder = new StreamsBuilder();

        JsonbSerde<FinancialMessage> financialMessageSerde = new JsonbSerde<>(FinancialMessage.class);

        builder.stream(
            INCOMING_TOPIC,
            Consumed.with(Serdes.Integer(), financialMessageSerde)
        )
        .filter(
            (key, message) -> checkCompliance(message)
        )
        .mapValues (
            checkedMessage -> performComplianceCheck(checkedMessage)
        )
        .to (
            INCOMING_TOPIC,
            Produced.with(Serdes.Integer(), financialMessageSerde)
        );  

        return builder.build();
    }

    public boolean checkCompliance (FinancialMessage rawMessage) {
        return (rawMessage.compliance_services);
    }

    public FinancialMessage performComplianceCheck(FinancialMessage checkedMessage) {
        checkedMessage.compliance_services = false;

        return checkedMessage;
    }

}

然而，我猜它被称为“毒丸”，但是由mq生成的一条消息（有效负载为'aloha'）会破坏它，我无法反序列化它。我猜原因是“aloha”不能被识别为字符串，因为它是单引号。我无法访问该数据的发送方式，因为它是通过mq发送的。有没有一种方法可以跳过处理这个不可反序列化的消息，直接从主题继续处理？