我正在尝试根据另一个查询提升查询结果。e、 g.从类别“1”中选择启用的项目，但结果是，我需要首先从品牌“2”中获取项目（得分加倍）。查询示例：

{    
   "query": {
      "bool": {
       "must":[
          {
            "bool": {
              "must":[
                {
                  "term":{
                    "category_path_1":"1"
                  }
                }
              ]
            }
          },
          {
            "bool":{
              "should":[
                {
                  "term":{
                    "status":"enabled"
                  }
                }
              ]
            }
          }
        ],
        "should": [
          {
              "function_score": {
                "query": { 
                  "bool": {
                    "must": [
                      {
                        "term": {
                          "brand": {
                             "value": "2"
                           }
                        }
                      }
                    ]
                  }
                },
                "boost": 2,
                "boost_mode": "multiply"
              }
          }
        ]
      }
    }
}

结果（简化）：

{
  "took" : 2,
  "timed_out" : false,
  "_shards" : {
    "total" : 1,
    "successful" : 1,
    "skipped" : 0,
    "failed" : 0
  },
  "hits" : {
    "total" : {
      "value" : 50,
      "relation" : "eq"
    },
    "max_score" : 4.3390245,
    "hits" : [
      {
        "_index" : "product_1",
        "_type" : "_doc",
        "_id" : "9",
        "_score" : 4.3390245,
        "_source" : {
          "category_path_1" : "1",
          "brand" : "2",
          "status" : "enabled"
        }
      },
      {
        "_index" : "product_1",
        "_type" : "_doc",
        "_id" : "21",
        "_score" : 4.3390245,
        "_source" : {
          "category_path_1" : "1",
          "brand" : "2",
          "status" : "enabled"
        }
      },
      {
        "_index" : "product_1",
        "_type" : "_doc",
        "_id" : "3",
        "_score" : 2.3390243,
        "_source" : {
          "category_path_1" : "1",
          "brand" : "1",
          "status" : "enabled"
        }
      }
    ]
  }
}

预期结果：

{
  "took" : 2,
  "timed_out" : false,
  "_shards" : {
    "total" : 1,
    "successful" : 1,
    "skipped" : 0,
    "failed" : 0
  },
  "hits" : {
    "total" : {
      "value" : 50,
      "relation" : "eq"
    },
    "max_score" : 7.3390245,
    "hits" : [
      {
        "_index" : "product_1",
        "_type" : "_doc",
        "_id" : "9",
        "_score" : 4.6780486,
        "_source" : {
          "category_path_1" : "1",
          "brand" : "2",
          "status" : "enabled"
        }
      },
      {
        "_index" : "product_1",
        "_type" : "_doc",
        "_id" : "21",
        "_score" : 4.6780486,
        "_source" : {
          "category_path_1" : "1",
          "brand" : "2",
          "status" : "enabled"
        }
      },
      {
        "_index" : "product_1",
        "_type" : "_doc",
        "_id" : "3",
        "_score" : 2.3390243,
        "_source" : {
          "category_path_1" : "1",
          "brand" : "1",
          "status" : "enabled"
        }
      }
    ]
  }
}

因此，品牌为“2”的商品 _score "4.33". 在同一查询中，但没有 function_score ，项有 _score 大约“2.33”。因此 _score 乘以 "boost": 2, "boost_mode": "multiply" 不象我预期的那样工作，它从 boost 而不是乘法。
查询自 function_score 可能更复杂，但结果是，我只需要乘以 _score 所选项目的值。