我正在尝试编写一个脚本,用表单中键入的新值更新数据库中存储的值
从表单中获取值:
$reviewTitle = $_POST['reviewTitle'];
$storeScore = $_POST['storeScore'];
$reviewContent = $_POST['reviewContent'];
将值更新到数据库
$sql = "UPDATE reviews SET reviewTitle=?, storeScore=?, reviewContent=? WHERE reviewID=?";
$stmt = $db->prepare($sql);
$stmt->bind_param('sisi', $reviewTitle, $storeScore, $reviewContent, $_POST['edit']);
$stmt->execute();
if ($stmt->error) {
echo "FAILURE!!! " . $stmt->error;
}
else echo "Updated {$stmt->affected_rows} rows";
header("Location: review?store=" . $store['storeName']);
我看不出这样做不起作用的原因,我是不是在语法上遗漏了什么?谢谢你的帮助
编辑:我添加了脚本输出的错误
Fatal error: Uncaught Error: Call to undefined method
PDOStatement::bind_param() in .
/home/o2q4e1ph6yl2/public_html/editreview.php:38 Stack trace: #0
/home/o2q4e1ph6yl2/public_html/review.php(54): include() #1 {main} .
thrown in /home/o2q4e1ph6yl2/public_html/editreview.php on line 38
1条答案
按热度按时间shyt4zoc1#
问题的答案是:
只花了4小时就搞定了