同一表上的左连接

aiazj4mn  于 2021-06-15  发布在  Mysql
关注(0)|答案(2)|浏览(328)

我有两个表,我试图左连接,但我没有得到预期的结果。
房间在不同的日子有多个孩子,但是孩子们只有在他们开始后才被计算在一个房间里,如果他们在那一天有时间分配的话。我想要达到的效果是这样的。

Room  | MaxNum | Mon(Week1) | Tue(Week1) | Mon(Week2) | Tue(Week2)
Blue  | 5      | 4          | 4          | 3          | 2
Green | 10     | 10         | 10         | 9          | 9  
Red   | 15     | 15         | 15         | 15         | 15

这是模式和一些数据。。。

create table Rooms(
  id       INT,
  RoomName VARCHAR(10),
  MaxNum   INT
);

create table Children (
  id          INT,
  RoomID      INT,
  MonHrs      INT,
  TueHrs      INT,
  StartDate   DATE
);

INSERT INTO Rooms VALUES (1, 'Blue', 5);
INSERT INTO Rooms VALUES (2, 'Green', 10);
INSERT INTO Rooms VALUES (3, 'Red', 15);

INSERT INTO Children VALUES (1, 1, 5, 0, '2018-12-02');
INSERT INTO Children VALUES (2, 1, 0, 5, '2018-12-02');
INSERT INTO Children VALUES (3, 1, 5, 5, '2018-12-09');
INSERT INTO Children VALUES (4, 1, 0, 5, '2018-12-09');
INSERT INTO Children VALUES (5, 2, 5, 0, '2018-12-09');
INSERT INTO Children VALUES (6, 2, 0, 5, '2018-12-09');

我遇到的问题是这个。这可能不是正确的方法。

SELECT R.RoomName, R.MaxNum,
       R.MaxNum - SUM(CASE WHEN C1.MonHrs > 0 THEN 1 ELSE 0 END) AS Mon1,
       R.MaxNum - SUM(CASE WHEN C1.TueHrs > 0 THEN 1 ELSE 0 END) AS Tue1,
       R.MaxNum - SUM(CASE WHEN C2.MonHrs > 0 THEN 1 ELSE 0 END) AS Mon2,
       R.MaxNum - SUM(CASE WHEN C2.TueHrs > 0 THEN 1 ELSE 0 END) AS Tue2
  FROM Rooms R
        LEFT JOIN Children C1 
          ON R.id = C1.RoomID
         AND C1.StartDate <= '2018-12-02'     
        LEFT JOIN Children C2
          ON R.id = C2.RoomID
         AND C2.StartDate <= '2018-12-09'
 GROUP BY R.RoomName;


在左连接中的行上发生了一个双向上的情况,这使计数偏离了方向,我不知道如何防止它们。如果将select替换为*

任何建议都会大有帮助。

wooyq4lh

wooyq4lh1#

您需要使用一个左联接,并将日期筛选器从联接条件移动到聚合:

SELECT R.id, R.RoomName, R.MaxNum
    , R.MaxNum - COUNT(CASE WHEN C.StartDate <= '2018-12-02' AND C.MonHrs > 0 THEN 1 END) AS Mon1
    , R.MaxNum - COUNT(CASE WHEN C.StartDate <= '2018-12-02' AND C.TueHrs > 0 THEN 1 END) AS Tue1
    , R.MaxNum - COUNT(CASE WHEN C.StartDate <= '2018-12-09' AND C.MonHrs > 0 THEN 1 END) AS Mon2
    , R.MaxNum - COUNT(CASE WHEN C.StartDate <= '2018-12-09' AND C.TueHrs > 0 THEN 1 END) AS Tue2
FROM Rooms R
LEFT JOIN Children C ON R.id = C.RoomID
GROUP BY R.id, R.RoomName, R.MaxNum
hc8w905p

hc8w905p2#

这类问题通常是由于在查询中过于宽泛的点上进行聚合而出现的,这将导致记录的重复计数。尝试聚合 Children 单独子查询中的表:

SELECT
    R.RoomName,
    R.MaxNum,
    R.MaxNum - C.Mon1 AS Mon1,
    R.MaxNum - C.Tue1 AS Tue1,
    R.MaxNum - C.Mon2 AS Mon2,
    R.MaxNum - C.Tue2 AS Tue2
FROM Rooms R
LEFT JOIN
(
    SELECT
        RoomID,
        COUNT(CASE WHEN MonHrs > 0 AND StartDate <= '2018-12-02'
                   THEN 1 END) AS Mon1,
        COUNT(CASE WHEN TueHrs > 0 AND StartDate <= '2018-12-02'
                   THEN 1 END) AS Tue1,
        COUNT(CASE WHEN MonHrs > 0 AND StartDate <= '2018-12-09'
                   THEN 1 END) AS Mon2,
        COUNT(CASE WHEN TueHrs > 0 AND StartDate <= '2018-12-09'
                   THEN 1 END) AS Tue2
    FROM Children
    GROUP BY RoomID
) C
    ON R.id = C.RoomID;

注意,我们可以通过在开始日期使用条件聚合来避免原始查询中的双左联接。
后期编辑:你甚至可能根本不需要子查询,q.v.@salman的答案。但我们的任何一个答案都应该解决重复计算的问题。

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