我的php中有以下内容。

$stmt = $conn->prepare("INSERT IGNORE INTO savesearch (user, searchedFor, sortOrder, buildURLString, aspectFilters, oneSignalId, totalEntries)
  VALUES (?, ?, ?, ?, ?, ?, ?)");
  $stmt->bind_param("sssssss", $user, $searchedFor, $sortOrder, $buildURLString, $aspectFilters, $oneSignalId, $totalEntries);

  // set parameters and execute
  $user = $_POST['user'];
  $searchedFor = $_POST["searchedFor"];
  $sortOrder = $_POST["sortOrder"];
  $buildURLString = $_POST["buildURLString"];
  $aspectFilters = $_POST["aspectFilters"];
  $oneSignalId = $_POST["oneSignalId"];
  $totalEntries = $_POST["totalEntries"];

  if ($stmt->execute()) {
    $output->success = true;
    echo json_encode($output);
  } else {
    $error->error = mysqli_error($conn);
    echo json_encode($error);
  }

但是，忽略没有被拾取，它将继续添加条目。有没有别的好办法来解决这个问题？
我想看看用户和网址是否相同，不要添加，回音重复条目。