有人能帮我把这个有说服力的查询转换成sql查询吗,因为我正在研究这段代码。我很难理解这段代码是什么,因为我是一个新的口才,但我有一些sql的经验。
$checkInDate = date("d-m-Y", strtotime($request->start_date));
$checkOutDate = date("d-m-Y", strtotime($request->end_date));
$availableRooms = $this->_availablerooms->from('availableRoom as r')
->selectRaw('*,r.roomDoorNum, r.isAvailable, rt.title as roomType,res.roomReservedID')
->join('roomtype as rt','rt.roomTypeID','=','r.roomTypeID')
->leftjoin('roomReserved as rr','rr.roomID','=','r.roomID')
->leftjoin('reservation as res','res.roomReservedID','=', DB::raw('rr.roomReservedID AND (res.reservationDate BETWEEN '."$checkInDate".' AND ' ."$checkOutDate". ' OR res.expiryDate BETWEEN '."$checkInDate".' AND ' ."$checkOutDate".')' ))
->get();
return $availableRooms;
1条答案
按热度按时间guykilcj1#
没人真的能帮你。明天,您可能需要一些其他查询来进入和探索。所以我的建议是安装https://github.com/barryvdh/laravel-debugbar 这个包和它将负责将雄辩的查询转换为原始查询。