你可以划分 account_id 按10创建一个范围，然后按除以的结果分组以获得所需的结果：

SELECT CONCAT(LPAD(FLOOR(account_id/10)*10,3, '0'), '-', LPAD(FLOOR(account_id/10)*10+9, 3, '0')) AS `range`,
       COUNT(*) AS number
FROM accounts
GROUP BY `range`

输出（对于演示中的一些示例数据）：

range       number
000-009     3
010-019     2
020-029     1
030-039     1
040-049     1
050-059     2

在dbfiddle上演示

你会用 group by :

select (case when account_id >= '000' and account_id <= '010' then '000-010'
             when account_id >= '011' and account_id <= '020' then '011-020'
             when account_id >= '021' and account_id <= '030' then '021-030'
             . . .
        end) as account_id_grp,
       count(*)
from accounts
group by account_id_grp
order by account_id_grp;

select t1.account_id ||'-'||t2.
     account_id,count(*) from 
     table t1 where account_id IN (Select account_id from 
      table t2 where t2.account_id-t1.account_id=10)`

我试着通过相关子查询获取表中帐户ID的差异