我合并了两个查询,其中返回3列(月、计数、目标),通过分别执行这两个查询,它将返回2条记录,这是正确的。但所有的联合只会给我一个值:
我的问题:
select s.month,COALESCE(max(s.count), NULL, 0) as count, COALESCE(max(s.targets), NULL, 0) as target from
(SELECT MONTHNAME(tm.meeting_date) as month, count(DISTINCT tm.meeting_id) as count, NULL as targets
FROM tig as t
left join tig_meeting as tm ON t.tig_code = tm.tig_code
WHERE tm.meeting_date IS NOT NULL AND tm.meeting_date != 0 AND t.school_district = 'Islamabad C3'
AND (tm.meeting_date BETWEEN "2018-07-01" AND "2018-09-30") AND tm.key_support <> 'QuarterlyTigMeetings' AND tm.key_support <> 'QTIG_by_SSA'
AND tm.key_support <> 'MTIG_by_SSA' AND tm.meeting_no NOT LIKE '%RF'
GROUP BY MONTH(tm.meeting_date)
UNION ALL
SELECT mpt.month, NULL as count, SUM(mpt.monthly_target) as targets
FROM meeting_plan_targets mpt
LEFT JOIN meeting_plans mp ON mp.id = mpt.meeting_plan_id
WHERE mp.district = 'Islamabad C3' AND mp.module_title = 1 AND mp.year = 2018 AND mp.quarter = "Quarter 4" GROUP BY mpt.month) s
group by MONTH(s.month)
参考请检查所附图片
2条答案
按热度按时间tp5buhyn1#
你可以在下面试试
o75abkj42#
s.month
是月份名称。MONTH(s.month)
行不通,因为MONTH()
函数要求其参数是日期或日期时间(或可以解析为日期或日期时间的字符串),而不是月份名称。使用
GROUP BY s.month
相反。