我想用 mysqli_stmt_bind_result() 但我觉得我用得不对。下面的代码获取用户名和密码，并在数据库中运行一个查询，如果匹配，则意味着返回成功。
但是，当我打印出行时，它是空的。我可能做错了什么？
我不打算使用 mysqli_stmt_get_result() 我知道这是怎么回事。我想利用 mysqli_stmt_bind_result 在这种情况下。

<?php

if ($_SERVER['REQUEST_METHOD'] == 'POST'){
    require 'dbh.inc.php';
    $email = $_POST['email'];
    $pass = $_POST['pass'];

    if (empty($email) || empty($pass)) {
      header("Location: ../login.php?error=emptyfields");
      exit();
    }
    else {
      $sql = "SELECT idUsers, emailUsers, firstNameUsers, lastNameUsers, pwdUsers, bdayUsers FROM users WHERE emailUsers = ?";
      $stmt = mysqli_stmt_init($conn);
      if (!mysqli_stmt_prepare($stmt, $sql)) {
        echo 'errorme';
        exit();
      }
      else {
        mysqli_stmt_bind_param($stmt ,"s", $email);
        mysqli_stmt_execute($stmt);
        mysqli_stmt_bind_result($stmt, $id_Users ,$email_Users, $first_NameUsers, $last_NameUsers, $pass_word, $bday_Users);
        if ($row=mysqli_stmt_fetch($stmt)) {
          $message = $row["$email"];
          echo "<script type='text/javascript'>alert('$message');</script>";
          $pwdCheck = password_verify($pass, $row['pwdUsers']);
          if ($pwdCheck == false) {
            echo 'wrongpass';
            exit();
          }
          else if($pwdCheck == true) {
            session_start();
            $_SESSION['userId'] = $row['idUsers'];
            $_SESSION['userName'] = $row['firstNameUsers'];
            echo 'success';
            exit();
          }
          else {
            echo 'noresults';
            exit();
          }
        }
        else {
          echo 'nouser';
          exit();
        }
      }
    }
}
else {
  header("Location: ../login.php");
  exit();
}
?>