我正在创建一个程序,其中我从一个表中选择的数据被随机分组。来自每个组的registrationid号被保存到另一个表中(作为外键),并且每个组成员都被分配一个groupid,该groupid随着创建的每个新组而自动递增。
$GroupSize = $_POST['groupsize'];
//Connect to the Server+Select DB
$con = mysqli_connect($host, $user, $password, $dbName) or die("Nope");
if (isset($_POST['create'])) {
//assign group id to groups created
//insert groupinformation to table from userInformation
$query = "SELECT RegistrationId FROM (Select * from userInformation order by RAND() LIMIT ".$GroupSize.") INTO groupInformation";
$result = mysqli_query($con, $query) or die ("query failed" . mysqli_error($con));
//display group and information
echo "<table border='1' >";
echo "<tr><th>RegId</th><th>Name</th><th>Address</th><th>Email</th></tr>";
while (($row = mysqli_fetch_row($result)) == true) {
echo "<tr><td>$row[0]</td><td>$row[1]</td><td>$row[2]</td><td>$row[3]</td></tr>";
}
echo "</table>";
//if group is less than 2 create error message
}
mysqli_close($con);
我的问题是无法将groupid分配给提取的结果,因为无法复制自动递增的数字。这是我的错误:
query failed Every derived table must have its own alias
这是我的表格
1条答案
按热度按时间blpfk2vs1#
让
GroupId
自动递增,然后再创建一列RandomGroupId
在groupInformation
,然后粘贴查询: