尝试使用peewee输入foreignkey字段时出现attributeerror

ckocjqey  于 2021-06-18  发布在  Mysql
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我真的花了最宝贵的时间试图找出我收到的错误消息的原因。
我正在编写一个web scraper,它使用python和beautifulsoup进行scraping,peewee进行数据库交互,将procycing stats中的数据刮到mysql数据库中。webscraper工作得非常好,但是我在将数据插入mysql表时遇到了一些问题。
首先,我使用peewee的 create_tables() 功能。在下面,我粘贴了peewee模型的代码,它包含在我调用的一个文件中 peewee_lib.py .

from peewee import *
from mysql_login_info import *

results_database = MySQLDatabase(mysql_db_name, user=mysql_uname, password=mysql_pw, host='localhost')

class BaseModel(Model):
    class Meta:
        database = results_database

class Rider(BaseModel):

    pcsid = IntegerField()
    name = CharField()

class Race(BaseModel):

    name = CharField()

class Result(BaseModel):

    name = CharField()
    year = IntegerField()
    date = DateField()

    position = IntegerField()
    points_pcs = IntegerField()

    race = ForeignKeyField(Race, backref='results')
    rider = ForeignKeyField(Rider, backref='results')

接下来,我使用一个文件 scrape_to_peewee.py 创建将我的类定义从我的刮库“绑定”在一起的类 scraper_lib.py 还有前面提到的peewee图书馆, peewee_lib.py .
这是我的密码 scrape_to_peewee.py :

import scraper_lib as pylib
import peewee_lib as pw

class Sheet_bind:

    def __init__(self, rider_obj, sheet):

        self.year = sheet.year
        self.rider = sheet.rider
        self.rows = []

        for row in sheet.rows:

            if row.row_type == "tour_header":
                pass
            else:
                temp_query = pw.Race.select().where(pw.Race.name == row.race)
                if not temp_query.exists():
                    temp_query = pw.Race(name=row.race)
                    temp_query.save()
                else:
                    pass

                temp_res = pw.Result(name=row.name,\
                                  year=sheet.year,\
                                  position=row.result,\
                                  points_pcs=row.points_pcs)

                if row.row_type in ["stage", "classification"]:
                    temp_res.name = row.race + ' ' + row.name
                temp_res.race=temp_query
                temp_res.rider=rider_obj
                temp_res.save()
            temp_query = None
            temp_res = None

class Rider_bind:

    def __init__(self, rider_id):

        self.rider_py = pylib.Rider(rider_id)
        self.rider_pw = pw.Rider(pcsid=self.rider_py.url_id, name=self.rider_py.name)
    self.rider_pw.save()

    def load_sheets(self, start_year, end_year):

        for year in xrange(start_year, end_year + 1):
            if year not in self.rider_py.sheets:
                self.rider_py.load_sheets(year, year)

            loaded_sheet = Sheet_bind(self.rider_pw, self.rider_py.sheets[year])
            loaded_sheet.save() 

def main():
    pw.results_database.connect()

main()

在将这个最终文件加载到解释器之后,我尝试将一个示例附加程序加载到数据库中。启动 Rider_bind 上课很顺利,我仔细检查了一遍,确保有一行已经写给了我的老师 rider mysql中的表。当我尝试将结果加载到数据库时 Rider_bind.load_sheets() 但是,我得到以下错误:

$ python
Python 2.7.15rc1 (default, Nov 12 2018, 14:31:15) 
[GCC 7.3.0] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> from scrape_to_peewee import *
>>> olly = Rider_bind("oliver-naesen")
>>> olly.load_sheets(2018, 2018)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "scrape_to_peewee.py", line 55, in load_sheets
    loaded_sheet = Sheet_bind(self.rider_pw, self.rider_py.sheets[year])
  File "scrape_to_peewee.py", line 33, in __init__
    temp_res.race=temp_query
  File "/home/trenza/.local/lib/python2.7/site-packages/peewee.py", line 3848, in __set__
    if obj != fk_value and self.name in instance.__rel__:
  File "/home/trenza/.local/lib/python2.7/site-packages/peewee.py", line 726, in __ne__
    return not (self == other)
  File "/home/trenza/.local/lib/python2.7/site-packages/peewee.py", line 723, in __eq__
    return self._hash == other._hash
AttributeError: 'NoneType' object has no attribute '_hash'

问题似乎与将一个peewee模型分配给foreignkey字段有关。当我把通话顺序颠倒过来 temp_res.rider = rider_obj 首先,它给了我同样的错误,回溯指向那个调用。
从peewee文档来看,foreignkey字段应该像将另一个peewee类作为值赋给它们一样简单。有人知道我错在哪里吗?任何帮助都将不胜感激。
谢谢您!
编辑:
不是这个问题的重复,因为它(据我所知)与 select 呼叫(上述问题中的问题)。

cs7cruho

cs7cruho1#

在指定属性时,需要将“temp\u query”解析为对象。

if not temp_query.exists():
                temp_query = pw.Race(name=row.race)
                temp_query.save()
            else:
                temp_query = temp_query.get()  # fixed.

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