你可以尝试像这样的方法

User::destroy($id)

在你的 web.php 路由文件，您已通过 {users} ，而不是通过 {id} :

Route::get('users/{id}/delete', [
    'uses' => '\App\Http\Controllers\UserController@delete',
])->name('user.delete');

在您的刀片视图中：

<td><a class="button is-outlined" href="{{route('users.delete',['id' => $user->id])}}" onclick="return confirm('Are you sure to want to delete this record?')" >Delete</a></td>`

在控制器中：

public function delete($id)
{
        User::where('id', $id)->delete();
        // or you can use User::destroy($id);
        return redirect()->back()->with('info', 'User deleted successfully'); 
}

将路线改为：

Route::get('users/{id}/delete', [
    'uses' => '\App\Http\Controllers\UserController@delete',
]);

然后检查数据库表是否已删除用户。如果不是，那么我认为这是您的数据库中的ci冲突，仅仅因为一个用户id是另一个表中的外键，您就不能删除它。

我会改变你的想法 route.php file 更简单的方法有助于理解：

Route::get('users/{id}/delete', 'UserController@delete')
->where(['id', => '[0-9]+'])
->name('user.delete');

在上面的路由上，您已经确保它只接受 id 是一个数字。此外，您还可以命名路由以简化代码结构，因此如果以后更改它，则不必继续在表单中更改它
然后，表单中的路由生成也会改变它：

href="{{route('user.delete', ['id' => $user->id])}}"

在你的控制器上

public function delete($id)
{
    $user = User::find($id);

    //Having a hold on your user model makes it able to also delete any other relationship it might have, if you so wish
    $user->delete();

    return redirect()
              ->back()
              ->with('info', 'User deleted successfully'); 
}

将路线改为：

Route::get('users/{id}/delete', [
    'as' => 'users.delete','uses' => '\App\Http\Controllers\UserController@delete',
]);

更改以下行：

<td><a class="button is-outlined" href="{{route('users.index', $user->id.'/delete/')}}" onclick="return confirm('Are you sure to want to delete this record?')" >Delete</a></td>

到

<td><a class="button is-outlined" href="{{route('users.delete',['id' => $user->id])}}" onclick="return confirm('Are you sure to want to delete this record?')" >Delete</a></td>