我有如下select语句和示例输出:-
select uph.creation_date, p.name,p.product_id from product p
left join user_product_history uph on p.product_id = uph.product_id
where uph.user_id = 124 order by uph.creation_date desc
如何按产品id和最新创建日期分组?请帮忙。谢谢您。
用php api.model文件编辑
// ~/user/product_history
public function product_history($data) {
$sql = 'select uph.creation_date,
p.name,
p.product_id
from product p
join user_product_history uph
on p.product_id = uph.product_id and
uph.user_id = ?
join (select product_id,
MAX(creation_date) AS max_creation_date
from user_product_history
where user_id = ?
group by product_id) dt
on dt.product_id = uph.product_id and
dt.max_creation_date = uph.creation_date
order by uph.creation_date desc';
$result = $this->db->query($sql, array($data['user_id']));
$records = array();
foreach( $result->result_array() as $r ) {
$r['product_id'] = (int) $r['product_id'];
$r['sub_category_id'] = (int) $r['sub_category_id'];
$r['merchant_id'] = (int) $r['merchant_id'];
if (!isset($r['price_discount'])) $r['price_discount'] = '';
$records[] = $r;
}
return $records;
}
2条答案
按热度按时间nqwrtyyt1#
首先,你不需要
Left Join
在这里,当你过滤的时候user_product_history
还有table。似乎您只想显示那些具有creation_date
对应user_id = 124
. 所以,你可以简单地使用Inner Join
相反。在派生表(子选择查询)中,确定
creation_date
每product_id
.现在,使用这个结果集连接到主表,在
product_id
以及creation_date
,以获取完整的行。请尝试以下操作:
mklgxw1f2#