我有一张如下的table:
日程安排
+-------+------------+--------+----------------+-------+---------+
| index | date | empid | dept | sfrom | slength |
+-------+------------+--------+----------------+-------+---------+
| 0 | 09-24-2018 | 943023 | RADIOLOGY | 03PM | 8 |
| 1 | 09-24-2018 | 891046 | SURGERY | 07AM | 8 |
| 2 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 3 | 09-24-2018 | 886190 | CARDIOLOGY | 03PM | 8 |
| 4 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 5 | 09-24-2018 | 891330 | SURGERY | 03PM | 8 |
| 6 | 09-24-2018 | 995561 | SURGERY | 11PM | 8 |
| 7 | 09-24-2018 | 967577 | MATERNITY | 03PM | 8 |
| 8 | 09-24-2018 | 913891 | PEDIATRICS | 03PM | 8 |
| 9 | 09-24-2018 | 939148 | EMERGENCY | 07AM | 8 |
| 10 | 09-24-2018 | 995636 | RADIOLOGY | 11PM | 8 |
| 11 | 09-24-2018 | 995561 | EMERGENCY | 11PM | 8 |
| 12 | 09-24-2018 | 967577 | SURGERY | 07AM | 8 |
| 13 | 09-24-2018 | 883069 | INTENSIVE CARE | 07AM | 8 |
| 14 | 09-24-2018 | 951876 | ONCOLOGY | 03PM | 8 |
| 15 | 09-24-2018 | 884866 | CARDIOLOGY | 07AM | 8 |
| 16 | 09-24-2018 | 864425 | ONCOLOGY | 03PM | 8 |
员工表
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| index | empid | lastName | firstName | emptype | cellphone | homephone | ftpt |
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| 0 | 919675 | Cermak | Vern | LPN | (138)7198-0862 | (655)2249-9926 | FT |
| 1 | 906704 | Paille | Lorilee | NULL | (858)1100-2722 | (377)1506-1986 | PT |
| 2 | 900486 | Ober | Shalanda | NULL | (210)1508-8132 | (820)1612-0197 | FT |
| 3 | 883367 | Clyburn | Jeffry | LPN | (420)7798-7220 | (476)7661-3070 | FT |
| 4 | 953807 | Quarles | Timmy | LPN | (513)2756-9892
如果我必须计算每个部门、每个员工类型和每个班次的总成本,我应该如何在sql中进行计算?
如果一次轮班包括午夜我的工资乘以25%?
我有一个示例输出,如下所示,但不知道如何做到这一点:
+------------+---------------+----------------+---------+
| DEPARTMENT | EMPLOYEE_TYPE | SHIFT | COST |
+------------+---------------+----------------+---------+
| Anesthesia | LPN | 7 AM –3 | $24,567 |
| Anesthesia | LPN | 3 PM –11PM | $18,546 |
| Anesthesia | LPN | 11 PM –7AM | $22,874 |
| Anesthesia | NA | 7 AM –3 PM | $9,764 |
| Anesthesia | NA | 3 PM –11 PM | $10,287 |
| Anesthesia | NA | 11 PM –7 AM | $6, 875 |
| Anesthesia | RN | 7 AM –3 PM | $33,123 |
+------------+---------------+----------------+---------+
到目前为止,这是我的sql语句:但是我应该如何让它工作呢?编辑1:
Select
t1.dept,
t2.emptype,
t1.sfrom,
t1.slength,
SUM(t1.slength) as hours
CASE WHEN CAST(STR_TO_DATE(sfrom,'%h%p') +
STR_TO_DATE(slength,'%H')) > STR_TO_DATE(23,'%H')
then (slength*10*1.25) else (slength*10) end as cost
from
schedule_2 as t1
Join (select
empid,
emptype
from
employees_2) as t2 ON t1.empid=t2.empid
GROUP BY
dept,
emptype,
slength;
编辑2:
Select
t1.dept,
t2.emptype,
t1.sfrom,
t1.slength,
SUM(t1.slength) as hours
CASE WHEN HOUR(STR_TO_DATE(sfrom,'%h%p') +
STR_TO_DATE(slength,'%H')) > 23
then (slength*10*1.25) else (slength*10)
from
schedule_2 as t1
Join (select
empid,
emptype
from`
employees_2) as t2 ON t1.empid=t2.empid
GROUP BY
dept,
emptype,
slength;
我得到以下错误,但似乎无法找出原因?
sql语法有错误;检查与您的mariadb服务器版本相对应的手册,以获得正确的语法,使用“case when hour(str_to_date(sfrom,'%h%p')+str_to_date(slength,'%h'))”>23,然后在第2行使用“case when hour”
1条答案
按热度按时间hivapdat1#
您可以在sql语句中使用case子句来表示成本字段。例如:
假设是每小时10美元。您可以根据您的业务规则设置夜班条件。