如何在aws上创建一个可以在aws中显示mysql数据的网页ui

sgtfey8w 于 2021-06-18 发布在 Mysql

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我在aws-rds-mysql服务器上有一个数据库。我想在我的网站上创建一个网页，可以给一个登录id和密码，让用户以一种干净的方式访问数据库。

mysql amazon-web-services user-interface web-applications webpage

来源：https://stackoverflow.com/questions/52543320/how-to-create-a-webpage-ui-on-aws-that-can-show-data-from-mysql-in-aws

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按热度按时间

ikfrs5lh1#

以下是连接到数据库并在网页上提供登录功能所需的基本脚本。
config.php-全局配置

<?php
   define('DB_SERVER', 'localhost:3036');
   define('DB_USERNAME', 'root');
   define('DB_PASSWORD', 'rootpassword');
   define('DB_DATABASE', 'database');
   $db = mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_DATABASE);
?>

login.php-登录函数

<?php
   include("config.php");
   session_start();

   if($_SERVER["REQUEST_METHOD"] == "POST") {
      // username and password sent from form 

      $myusername = mysqli_real_escape_string($db,$_POST['username']);
      $mypassword = mysqli_real_escape_string($db,$_POST['password']); 

      $sql = "SELECT id FROM admin WHERE username = '$myusername' and passcode = '$mypassword'";
      $result = mysqli_query($db,$sql);
      $row = mysqli_fetch_array($result,MYSQLI_ASSOC);
      $active = $row['active'];

      $count = mysqli_num_rows($result);

      // If result matched $myusername and $mypassword, table row must be 1 row

      if($count == 1) {
         session_register("myusername");
         $_SESSION['login_user'] = $myusername;

         header("location: welcome.php");
      }else {
         $error = "Your Login Name or Password is invalid";
      }
   }
?>
<html>

welcome.php-成功登录后的欢迎页面

<?php
   include('session.php');
?>
<html">

   <head>
      <title>Welcome </title>
   </head>

   <body>
      <h1>Welcome <?php echo $login_session; ?></h1> 
      <h2><a href = "logout.php">Sign Out</a></h2>
   </body>

</html>

logout.php-成功注销后重定向到登录

<?php
   session_start();

   if(session_destroy()) {
      header("Location: login.php");
   }
?>

session.php-验证会话

<?php
   include('config.php');
   session_start();

   $user_check = $_SESSION['login_user'];

   $ses_sql = mysqli_query($db,"select username from admin where username = '$user_check' ");

   $row = mysqli_fetch_array($ses_sql,MYSQLI_ASSOC);

   $login_session = $row['username'];

   if(!isset($_SESSION['login_user'])){
      header("location:login.php");
   }
?>

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如何在aws上创建一个可以在aws中显示mysql数据的网页ui

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