我想用php创建一个mysql表，在这个表中我可以根据mysql数据库的特定用户的表列值设置表名。在下面的代码中，我试图通过将表名与存储名称（来自数据库）的变量相等来实现这一点，但每次出现错误都意味着它不起作用，请帮助我！

<?php
session_start();
include_once 'dbconnect2.php';

if(!isset($_SESSION['user']))
{
  header("Location: index.php");
}
$res=mysqli_query($con, "SELECT * FROM users WHERE user_id=".$_SESSION['user']);
$userRow=mysqli_fetch_assoc($res);

if($userRow['tableid']!=1)
{
    $user_id = $userRow['user_id'];

    $createtable="  CREATE TABLE `id`='$user_id' (
                        `id` int(5) NOT NULL,
                        `topic` int(5) NOT NULL,

                        `ptopic` varchar(25) NOT NULL,
                        ADD PRIMARY KEY (`id`)

                    ) ENGINE=MyISAM DEFAULT CHARSET=latin1";
    $resulttid = mysqli_query($con, $createtable);
    if($resulttid)   {
        $tablequery = "UPDATE `users` SET `tableid`='1' WHERE `user_id` = $user_id";      
        $resulttblquery = mysqli_query($con, $tablequery); 
    }else{ 
        echo "error";
    }
}
?>