当我在postman上测试时，这个api工作得很好，但当我试图通过在url中传递id来签入浏览器时，它显示出错误。http://192.168.43.88/mydatabase/delete.php?id=1 当我使用get方法时，我就可以在url中传递值，但是为什么我在post方法中会出错呢。

if($_SERVER['REQUEST_METHOD'] == 'POST') {
    $id = $_POST['id'];
    if($id == '') {
        echo 'please provide required value';
    } else {
        require_once('connection.php');
        $sql = "SELECT * FROM circle_detail WHERE id='$id' AND deleted='0' ";
        $check = mysqli_fetch_array(mysqli_query($conn, $sql));
        if(isset($check)) {
            $sql = "UPDATE  circle_detail SET deleted='1' WHERE id='$id'";
            if(mysqli_query($conn, $sql)) {
                echo 'marked as deleted';
            } else {
                echo 'oops! Please try again!';
            } 
        } else { 
            echo 'not found';
        }
        mysqli_close($conn);
    }
} else {
    echo 'error';
}