我认为这是最简单的方法：

select min(daily_price), min(weekly_price)
    from table 
    where element_id = 2
    AND year(since) = (select max(year(since))
                       from table
                       where element_id = 2);

如果要使用联接而不是子查询，请执行以下操作：

select min(daily_price), min(weekly_price)
from table a, (select max(year(since)) as year, element_id
                     from table
                     where element_id = 2) b
where a.element_id = 2
and a.element_id = b.element_id
and year(since) = b.year;

您可以将join与year、min daily和min weekly子查询一起使用

select  a.id, a.year, b. min_daily, c.min_weekly 
  from  (

    select id, max(year(until)) year 
    from my_table  
    group by id 

    ) a 
    inner join  (
    select id, year(until) year,  min(daily_price)  min_daily
    from my_table  
    group by id ,  year(until)  

    ) b on a.id = b.id and a.year=b.year 

    inner join  (
      select  id,  year(until) year, min(weekly_price) min_weekly
      from my_table  
      group by id ,  year(until) 
      ) c on a.id = c.id and a.year=c.year

你可以用这个

SELECT MIN(daily_price) as minDailyPrice, Max(weekly_price) as maxWeeklyPrice 
FROM yourTable 
WHERE until <= 'current_year_here' 
ORDER BY until DESC 
LIMIT 1