public static void main(String[] args) {
    Map<String, LinkedList<Object>> map = new HashMap<>();
    LinkedList<Object> data = new LinkedList<>();
    data.add(2);
    data.add(3);
    map.put("id", data);

    data = new LinkedList<>();
    data.add("Rohit");
    data.add("Iravati");
    map.put("name", data);

    data = new LinkedList<>();
    data.add("SE");
    data.add("SSE");
    map.put("jobrole", data);

    data = new LinkedList<>();
    data.add(100);
    data.add(200);
    map.put("salary", data);

    for (int i = 0; i < map.get("id").size(); i++) {
        Object id = map.get("id").get(i);
        Object name = map.get("name").get(i);
        Object jobrole = map.get("jobrole").get(i);
        Object salary = map.get("salary").get(i);
        // TODO Use above values to create your query.
        System.out.println(id + "-" + name + "-" + jobrole + "-" + salary);
    }

}

可以使用for循环遍历所有数据，并一次生成一个查询字符串
也许是这样的

for(int j = 0; j < mapOfData.get("ID").length(); j++){
     strID = mapOfData.get("ID").get(j);
     strName = mapOfData.get("Name").get(j);

     query = "INSERT INTO TABLE VALUES (" + strID + ", " + strName + ")";
}

您遍历Map的整个长度（假设Map中没有丢失的数据），访问每个LinkedList并从中获取值。

这是一种不好的方法，但您当前的数据结构并没有给我留下太多选择。

public static void main(String[] args) {

    //GIVEN
    Map<String, LinkedList<Object>> data = new HashMap<>();
    data.put("id", Stream.of(1, 2, 3)
            .collect(Collectors.toCollection(LinkedList::new)));
    data.put("name", Stream.of("a", "b", "c")
            .collect(Collectors.toCollection(LinkedList::new)));
    data.put("jobrole", Stream.of("x", "y", "z")
            .collect(Collectors.toCollection(LinkedList::new)));
    data.put("salary", Stream.of(10.0, 20.0, 30.0)
            .collect(Collectors.toCollection(LinkedList::new)));

    //Let's fix your data structure first
    Employee[] employeesArr = null;
    for (Map.Entry<String, LinkedList<Object>> entry : data.entrySet()) {
        int count = 0;
        if (employeesArr == null) {
            employeesArr = new Employee[entry.getValue().size()];
            for (int i = 0; i < employeesArr.length; i++) {
                employeesArr[i] = new Employee();
            }
        }
        switch (entry.getKey()) {
            case "id":
                for (Object o : entry.getValue()) {
                    employeesArr[count++].setId((Integer) o);
                }
                break;
            case "name":
                for (Object o : entry.getValue()) {
                    employeesArr[count++].setName((String) o);
                }
                break;
            case "jobrole":
                for (Object o : entry.getValue()) {
                    employeesArr[count++].setRole((String) o);
                }
                break;
            case "salary":
                for (Object o : entry.getValue()) {
                    employeesArr[count++].setSalary((Double) o);
                }
                break;
        }
    }

    //employeesArr is a much better data structure
    for (int i = 0; i < employeesArr.length; i++) {
        //use PreparedStatement or an ORM
        System.out.println("insert into DBROLTA.Employee(id, name, jobrole, salary) values ("
                + employeesArr[i].getId() + ", '"
                + employeesArr[i].getName() + "', '"
                + employeesArr[i].getRole() + "', "
                + employeesArr[i].getSalary()
                + ");");
    }

}

员工.java

public class Employee {
    private int id;
    private String name;
    private String role;
    private double salary;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    //other getters/setters
}

在Map中存储键和相应的值数组，将键存储为id，将自定义对象存储为value。
其中custom object是具有id、name、jobrole和salary属性的对象。
创建Map并将自定义对象存储到id，这样您就可以轻松地检索对象、创建sql语句并执行它们。

Map<Interger, CustomObject> = new HashMap<Integer, CustomObject>

对于多个inset查询执行，请使用批插入和批执行方法，这是为了避免多个数据库命中。
请参阅：如何从java执行多个sql语句以执行批更新操作。