你可以试试这个。
$date=date\u create（从excel中传递日期）；日期格式（$date，“y/m/d h:i:s”）；

如果这些是您必须处理的唯一日期，则以下代码将起作用：

$dates = [
    "01/01/2018",
    "01/01/18",
    "01.01.2018",
    "01.01.18",
    "01-01-2018",
    "01-01-18",
    "01.Jan.18",
    "01-Jan-18",
];

foreach($dates as $date){
    $dt_array = preg_split("/[^A-Za-z0-9]/", $date);
    //Break apart the date string using any non-alphanumeric character as the delimiter

    var_dump($dt_array);
    //Just for demonstration purposes

    $day = $dt_array[0];
    // Grab the day

    if(is_numeric($dt_array[1])){
        $month = $dt_array[1];
    } else {
        $dp = date_parse($dt_array[1]);
        $month = $dp['month'];
    }
    //The month is a little bit more complex,
    //because at times it's an integer, at times it's a string,
    //and we want it to always be a integer

    $year = $dt_array[2];
    //Grab the year

    $dt = new DateTime("{$year}-{$month}-{$day}");
    //The y-m-d format is flexible,
    //because it will accept yyyy and yy
    //and since your m and d are integers,
    //it will work even if they don't have a leading zero.

    var_dump($dt->format('Y-m-d'));
    //Just for demonstration purposes
}