我试图开发一个登录表单，所以我上网，并选择了一个代码。我创建了一个名为“company”的数据库，表“login”中有字段；id、用户名和密码。我在表中保存了一些条目。
当我尝试登录时，我得到一个响应；页面未正确重定向；firefox检测到服务器正在以一种永远无法完成的方式重定向对此地址的请求。此问题有时可能是由于禁用或拒绝接受Cookie造成的。
我不知道怎么了。下面是我的代码：index.php
<?php
include('login.php'); // Includes Login Script
if(isset($_SESSION['login_user'])){
header("location: profile.php");
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Login Form in PHP with Session</title>
<link href="style.css" rel="stylesheet" type="text/css">
</head>
<body>
<div id="main">
<h1>PHP Login Session Example</h1>
<div id="login">
<h2>Login Form</h2>
<form action="" method="post">
<label>UserName :</label>
<input id="name" name="username" placeholder="username" type="text">
<label>Password :</label>
<input id="password" name="password" placeholder="**********" type="password">
<input name="submit" type="submit" value=" Login ">
<span><?php echo $error; ?></span>
</form>
</div>
</div>
</body>
</html>登录.php
<?php
session_start(); // Starting Session
$error=''; // Variable To Store Error Message
if (isset($_POST['submit'])) {
if (empty($_POST['username']) || empty($_POST['password'])) {
$error = "Username or Password is invalid";
}
else
{
// Define $username and $password
$username=$_POST['username'];
$password=$_POST['password'];
// Establishing Connection with Server by passing server_name, user_id and password as a parameter
$connection = mysqli_connect("localhost", "root", "", "company");
// To protect MySQL injection for Security purpose
// SQL query to fetch information of registerd users and finds user match.
$query = mysqli_query($connection, "select * from login where password='$password' AND username='$username'");
$rows = mysqli_num_rows($query);
if ($rows == 1) {
$_SESSION['login_user']=$username; // Initializing Session
} else {
$error = "Username or Password is incorrect";
}
mysqli_close($connection); // Closing Connection
}
}
?>注销.php
<?php
session_start();
if(session_destroy()) // Destroying All Sessions
{
header("Location: index.php"); // Redirecting To Home Page
}
?>配置文件.php
<?php
include('session.php');
?>
<!DOCTYPE html>
<html>
<head>
<title>Your Home Page</title>
<link href="style.css" rel="stylesheet" type="text/css">
</head>
<body>
<div id="profile">
<b id="welcome">Welcome : <i><?php echo $login_session; ?></i></b>
<b id="logout"><a href="logout.php">Log Out</a></b>
</div>
</body>
</html>会话.php
<?php
// Establishing Connection with Server by passing server_name, user_id and password as a parameter
$connection = mysqli_connect("localhost", "root", "","company");
session_start();// Starting Session
// Storing Session
$user_check=$_SESSION['login_user'];
// SQL Query To Fetch Complete Information Of User
$ses_sql=mysqli_query("select username from login where username='$user_check'", $connection);
$row = mysqli_fetch_assoc($ses_sql);
$login_session =$row['username'];
if(!isset($login_session)){
mysqli_close($connection); // Closing Connection
header('Location: index.php'); // Redirecting To Home Page
}
?>谢谢您。
1条答案
按热度按时间wwtsj6pe1#
问题解决了。
我已连接到另一个具有更多字段的表，这是；id，名字，用户名和密码。
我编辑了session.php并使用firstname修改了mysqli\u查询，其中username是$user\u check。我现在正在打印登录用户的名字。
谢谢你们。