我有这个sql查询,它看起来很混乱,我想知道如何将它转换为codeigniter活动记录查询。
我曾考虑过这样的循环:
for ( $i=1 ; $i<=5 ; $i++) {
${'line'.$i} = $this->staffrequisition_model->getRequestsToProcess($i,$staffInfo->position_depth,$staffInfo->department_group);
}
$data = array_merge($line1, $line2, $line3, $line4, $line5);
在我的模型中使用此方法
public function getRequestsToProcess($i,$depth,$departmentGroup)
{
$this->db->select('*, ns_request_info.idx as request_idx, ns_staff_info.idx as staff_idx');
$this->db->from('ns_request_info');
$this->db->join('ns_staff_info', 'ns_request_info.requested_by_idx = ns_staff_info.member_idx');
$this->db->where('line'.$i.'', $depth);
$this->db->where('line'.$i.'_action', 'PENDING');
if($departmentGroup!='HIGHER TIER'){ $this->db->where('ns_staff_info.department_group', $departmentGroup); }
$this->db->where('status', 'PENDING');
$this->db->or_where('status', 'ONGOING');
$this->db->where('line'.$i.'', $depth);
$this->db->where('line'.$i.'_action', 'PENDING');
if($departmentGroup!='HIGHER TIER'){ $this->db->where('ns_staff_info.department_group', $departmentGroup); }
$this->db->order_by('idx', 'desc');
$query = $this->db->get();
return $query->result_array();
}
但我意识到,对所有这些元素进行数组合并会破坏结果的id排序。
这里有我的sql查询,我不知道如何将其转换为codeigniter活动记录查询。
SELECT *, ns_request_info.idx as request_idx, ns_staff_info.idx as staff_idx
FROM `ns_request_info`
INNER JOIN `ns_staff_info`
ON ns_request_info.requested_by_idx = ns_staff_info.member_idx
WHERE (
(ns_request_info.line1=1 AND ns_request_info.line1_action='PENDING') OR
(ns_request_info.line2=1 AND ns_request_info.line2_action='PENDING') OR
(ns_request_info.line3=1 AND ns_request_info.line3_action='PENDING') OR
(ns_request_info.line4=1 AND ns_request_info.line4_action='PENDING') OR
(ns_request_info.line5=1 AND ns_request_info.line5_action='PENDING')
) AND (ns_request_info.status='PENDING' OR ns_request_info.status='ONGOING')
ORDER BY ns_request_info.idx DESC
我希望你们能帮我。
2条答案
按热度按时间wgx48brx1#
尝试以下操作:
iswrvxsc2#