mysqli\u query()期望参数1是mysqli,字符串在第118行的c:\xampp\htdocs\payroll\u system\php\function.php中给出

mctunoxg  于 2021-06-20  发布在  Mysql
关注(0)|答案(1)|浏览(210)

我有个警告,我找不到问题所在。我现在有点生疏了,因为我毕业后就没写过代码。
警告:mysqli\u query()要求参数1为mysqli,字符串在第118行的c:\xampp\htdocs\payroll\u system\php\function.php中给出,未连接到数据库进行获取
这是那行的代码

$emps_checks="SELECT * FROM `information_tbl` WHERE `F_NAME` LIKE '$f_n' AND `M_NAME` LIKE '$m_n' AND `L_NAME` LIKE '$l_n'";
$checker_emp=mysqli_query($con,$emps_checks)or die("not connected to database for fetching");
$emp_result=mysqli_num_rows($checker_emp);
0aydgbwb

0aydgbwb1#

请确认您的 $con 应该是

$con= mysqli_connect($db_host,$db_username,$db_pass, "mrmagicadam");
if (mysqli_connect_errno())
{
   echo "Failed to connect to MySQL: " . mysqli_connect_error();exit;
}

相关问题