mysql查询由于日期不同而产生重复

ql3eal8s  于 2021-06-20  发布在  Mysql
关注(0)|答案(2)|浏览(326)

这个查询给出的正是它所要求的,但问题是,这不是我想要的,我似乎无法摆脱重复和其他职位的主题似乎不适用。它用于销售报告,它从日历中提取日期,但有时同一销售在需要回拨时有多个日历事件。
日历表只有id、title、location、start和quote字段,其余字段来自quoterequests,这是mysql。

SELECT qr.ID AS ID, 
c.ID AS CalendarID, 
DATE_FORMAT(QuoteDate,'%m-%d-%Y') AS QuoteDate, 
DATE_FORMAT(`Start`,'%m-%d-%Y') AS VerDate, 
TIME_FORMAT(`Start`,'%h:%i %p') AS VerTime, 
Name, MakeModel, CONCAT_WS('-',Prefix, Telephone) AS Phone, 
Email, 
Address, 
City, 
State, 
Zipcode, 
MilesQuoted, 
AmtQuoted, 
AmtCharged, 
ServiceFee 
FROM quoterequests qr 

JOIN calendar c 
ON Quote = qr.ID 

WHERE AmtCharged > 0 
AND YEAR(`Start`) = 2015 
ORDER BY UNIX_TIMESTAMP(`Start`) ASC
fslejnso

fslejnso1#

也许不必要的复杂,但这似乎做的把戏,而我是在它,我意识到,报价显然是一个保留字,所以我回勾它。结果发现,主要的问题,正如所指出的,是缺乏分钟,但我没有意识到,它可以在多个地方使用。一旦我这么做了,它就给出了正确的结果:

SELECT 
        ID,
        DATE_FORMAT(QuoteDate,'%m-%d-%Y') AS QuoteDate,
        DATE_FORMAT(MIN(c.`Start`),'%m-%d-%Y') AS VerDate,
        TIME_FORMAT(MIN(c.`Start`),'%h:%i %p') AS VerTime,

        Name, MakeModel, CONCAT_WS('-',Prefix, Telephone) AS Phone,
        Email,
        Address,
        City,
        State,
        Zipcode,
        MilesQuoted,
        AmtQuoted,
        AmtCharged,
        ServiceFee

FROM quoterequests qr 

LEFT JOIN (SELECT `Quote`, 
                `Start`, 
                MIN(UNIX_TIMESTAMP(`Start`)) AS `TimeStamp`
                FROM calendar c
                WHERE YEAR(`Start`) = 2015 
                GROUP BY ID, `Quote`, `Start` 
                ORDER BY UNIX_TIMESTAMP(`Start`) ASC) AS c 
        ON qr.ID = c.`Quote` 
WHERE AmtCharged > 0 
AND YEAR(c.`Start`) = 2015 
GROUP BY `Quote` 
ORDER BY UNIX_TIMESTAMP(MIN(c.`Start`)) ASC
yzuktlbb

yzuktlbb2#

没有足够的信息来回答这个问题,但根据经验:
group by仅在将AGRAGATE函数(min、max、count等)与普通列混合时使用。它不是用来删除重复项的。
要删除重复项,请使用 SELECT DISTINCT

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