我需要数据库中的条目总数。
问：为什么行“print\r（$rows）”返回“array（[count（id）]=>79）”而行“$recordcount=count（$row）；“回音”
记录计数=“$“记录计数；”返回“记录计数=1”。
我已经尝试了大量不同版本的代码，但我不能在这里全部键入，否则要花很长时间才能阅读。下面是代码的当前版本，它给了我上面提到的意外结果：

// create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// check connection
if ($conn->connect_error) {
die("connection failed: " . $conn->connect_error);
}

$sql = "SELECT * FROM games ORDER BY id DESC LIMIT $startRow, $rowsPerPage";
$result = $conn->query($sql);

$sql = "SELECT COUNT(id) FROM games";
$results = $conn->query($sql);
$row = $results->fetch_assoc();
print_r($row);
$recordCount = Count($row);
echo "<br/> record count = " . $recordCount;

$totalPages = ceil($recordCount / $rowsPerPage);
$pagination = "<div class='pagination'>";

for ($i = 0; $i <= $totalPages; $i++) {
  $pagination .= "<a href='index.php?page=" . $i . "'>" . $i . "</a>";
  echo 'wtf!';
}

$pagination .= "</div>";
echo ' <br/> pagination = ' . $pagination;

多亏了各位英雄，我现在已经纠正了这一点：如果2018年有人在网上阅读并发现许多不正确的实现：

$sql = "SELECT COUNT(id) as countid FROM games";
$results = $conn->query($sql);
$row = $results->fetch_assoc();

$recordCount = $row["countid"]; // the countid gives me the total i expected :DDDD
echo "<br/> record count = " . $recordCount;