我有一个包含游戏细节的表,这个表叫做 match
,每个匹配可以有n个目标,这些目标存储在表中 goal
.
假设我有以下情况 match
:
id = 2564824
home_team_half_time_score = 2
home_team_score = 4
away_team_half_time_score = 0
away_team_score = 0
所以这个记录意味着 match
对于主队来说是4比0结束的,我想知道的是:我怎样才能得到唯一的机会 goals
第一次得分?在这种情况下,第一次有两个进球,并且具有以下id:
id | match_id | result | minute
16092 2564824 1 - 0 15
16093 2564824 2 - 0 43
16094 2564824 3 - 0 63
16095 2564824 4 - 0 78
我只需要拿到 minute
每个目标的字段,如何设置查询?
架构
CREATE TABLE IF NOT EXISTS `swp`.`match` (
`id` INT NOT NULL,
`round_id` INT NULL,
`datetime` DATETIME NULL,
`status` INT NULL,
`gameweek` INT NULL,
`home_team_id` INT NULL,
`home_team_half_time_score` INT NULL,
`home_team_score` INT NULL,
`home_extra_time` INT NULL,
`home_penalties` INT NULL,
`away_team_id` INT NULL,
`away_team_half_time_score` INT NULL,
`away_team_score` INT NULL,
`away_extra_time` INT NULL,
`away_penalties` INT NULL,
`venue_id` INT NULL,
`venue_attendance` INT NULL,
`aggregate_match_id` INT NULL,
PRIMARY KEY (`id`),
INDEX `home_team_id_idx` (`home_team_id` ASC),
INDEX `away_team_id_idx` (`away_team_id` ASC),
INDEX `venue_id_idx` (`venue_id` ASC),
INDEX `match_status_id_idx` (`status` ASC),
INDEX `FK_competition_rounds_match_round_id_idx` (`round_id` ASC),
INDEX `FK_match_match_aggregate_match_id_idx` (`aggregate_match_id` ASC),
CONSTRAINT `FK_team_match_home_team_id`
FOREIGN KEY (`home_team_id`)
REFERENCES `swp`.`team` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_team_match_away_team_id`
FOREIGN KEY (`away_team_id`)
REFERENCES `swp`.`team` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_venue_match_venue_id`
FOREIGN KEY (`venue_id`)
REFERENCES `swp`.`venue` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_match_status_match_status_id`
FOREIGN KEY (`status`)
REFERENCES `swp`.`match_status` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_competition_rounds_match_round_id`
FOREIGN KEY (`round_id`)
REFERENCES `swp`.`competition_rounds` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_match_match_aggregate_match_id`
FOREIGN KEY (`aggregate_match_id`)
REFERENCES `swp`.`match` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
Thanks for any help.
CREATE TABLE IF NOT EXISTS `swp`.`goal` (
`id` INT NOT NULL AUTO_INCREMENT,
`team_id` INT NOT NULL COMMENT 'Team that has scored.',
`player_marker_id` INT NOT NULL,
`player_assist_id` INT NULL,
`match_id` INT NOT NULL,
`minute` VARCHAR(45) NOT NULL,
`result` VARCHAR(45) NULL,
`type` INT NOT NULL COMMENT 'All the status that a goal can assume.',
INDEX `player_marker_id_idx` (`player_marker_id` ASC),
INDEX `player_assist_id_idx` (`player_assist_id` ASC),
INDEX `match_id_idx` (`match_id` ASC),
PRIMARY KEY (`id`),
INDEX `FK_goal_type_goal_goal_type_id_idx` (`type` ASC),
INDEX `FK_team_goal_team_id_idx` (`team_id` ASC),
CONSTRAINT `FK_player_goal_player_marker_id`
FOREIGN KEY (`player_marker_id`)
REFERENCES `swp`.`player` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_player_goal_player_assist_id`
FOREIGN KEY (`player_assist_id`)
REFERENCES `swp`.`player` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_match_goal_match_id`
FOREIGN KEY (`match_id`)
REFERENCES `swp`.`match` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_goal_type_goal_goal_type_id`
FOREIGN KEY (`type`)
REFERENCES `swp`.`goal_type` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `FK_team_goal_team_id`
FOREIGN KEY (`team_id`)
REFERENCES `swp`.`team` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
更新
实际查询:
$query = "SELECT m.*,
t.name AS team_name,
t.id AS team_id,
l.position AS team_rank,
COUNT(CASE WHEN g.type = 5 THEN 1 END) AS failed_to_score,
FROM `match` m
LEFT JOIN goal g ON m.id = g.match_id
LEFT JOIN team t ON t.id = :team_id
LEFT JOIN league_ranking l ON l.team_id = :team_id AND l.round_id = :round_id
WHERE m.round_id = :round_id
AND m.status = 5 ";
1条答案
按热度按时间eh57zj3b1#
如果这是你的出发点:
如果这确实是您预期的结果,那么您必须显示输入数据才能获得此结果
未经测试
这个综合查询将停止对上半场的每一场比赛的分析。我会把这两个问题分开