php实现多级菜单？

798qvoo8 于 2021-06-20 发布在 Mysql

关注(0)|答案(3)|浏览(439)

我试图使一个菜单，是一个主菜单，去2级深（子菜单和子菜单）。
我以前也用过concat组，但那只是1级深。事实上，这是两个层次的深度真的把我的最佳实践的循环。

CREATE TABLE `database`.`main_menu` ( `main_menu_id` INT(11) NOT NULL AUTO_INCREMENT , `main_menu_name` VARCHAR(255) NOT NULL , PRIMARY KEY (`main_menu_id`)) ENGINE = InnoDB;

CREATE TABLE `database`.`sub_menu` ( `main_menu_id` INT(11) NOT NULL , `sub_menu_id` INT(11) NOT NULL AUTO_INCREMENT , `sub_menu_name` VARCHAR(255) NOT NULL , PRIMARY KEY (`sub_menu_id`)) ENGINE = InnoDB;

CREATE TABLE `database`.`sub_sub_menu` ( `main_menu_id` INT(11) NOT NULL , `sub_menu_id` INT(11) NOT NULL , `sub_sub_menu_id` INT(11) NOT NULL AUTO_INCREMENT , `sub_sub_menu_name` VARCHAR(255) NOT NULL , PRIMARY KEY (`sub_sub_menu_id`)) ENGINE = InnoDB;

INSERT INTO `main_menu` (`main_menu_id`, `main_menu_name`) VALUES (NULL, 'Food'), (NULL, 'Treats')

INSERT INTO `sub_menu` (`main_menu_id`, `sub_menu_id`, `sub_menu_name`) VALUES ('1', NULL, 'Duck'), ('1', NULL, 'Chicken')
INSERT INTO `sub_menu` (`main_menu_id`, `sub_menu_id`, `sub_menu_name`) VALUES ('2', NULL, 'Bacon Bits'), ('2', NULL, 'Dental')

INSERT INTO `sub_sub_menu` (`main_menu_id`, `sub_menu_id`, `sub_sub_menu_id`, `sub_sub_menu_name`) VALUES ('1', '1', NULL, 'In Gravy'), ('1', '2', NULL, 'in Soup')

INSERT INTO `sub_sub_menu` (`main_menu_id`, `sub_menu_id`, `sub_sub_menu_id`, `sub_sub_menu_name`) VALUES ('2', '3', NULL, 'Sticks'), ('2', '4', NULL, 'Chunks')

mysql查询：

SELECT ssm.sub_sub_menu_name  as    sub_sub_menu_name ,
sm.sub_menu_name  as    sub_menu_name ,
mm.main_menu_name  as   main_menu_name ,

ssm.sub_sub_menu_id  as     sub_sub_menu_id ,
sm.sub_menu_id  as      sub_menu_id ,
mm.main_menu_id  as     main_menu_id 

FROM        main_sub_sub_menu  as ssm
LEFT JOIN main_menu as mm
    ON mm.main_menu_id  = ssm.main_menu_id 
LEFT JOIN sub_menu as sm
    ON sm.sub_menu_id   = ssm.sub_menu_id  

ORDER BY ssm.sub_sub_menu_id, sm.sub_menu_id, ssm.main_menu_id

php在此介绍如何将信息分类：

<?php $cat = $getData->get_menu_categories(); //SQL Query above with PDO
$i = 1;
$j = 1;
for($a=0; $a<= count($cat); $a++){
        if($i == $cat[$a]['main_menu_id']){
            for($j=1; $j < count($cat[$a]['sub_menu_id']); $j++){ // Was getting stuck here because I can't count it unless it is an array
                 //Would show each submenu name, then I would make another for loop for the sub sub menu 
            }
        }else{
            $i++;
        }

输出将是
主菜单
子菜单
子菜单
我在列清单 <ul><li> 样式html菜单列表），基本上是一棵树。

mysql php

来源：https://stackoverflow.com/questions/50959418/how-to-do-multilevel-menu-the-correct-way-with-mysql-php

3条答案

按热度按时间

oewdyzsn1#

|---------------------|------------------|------------------|
|     id              |  menu_name       |   parent_id      |
|---------------------|------------------|------------------|
|      1              |Main Menu         |     null         |
|---------------------|------------------|------------------|
|      2              |sub Menu          |      1           |
|---------------------|------------------|------------------|
|      3              |sub sub Menu      |      2           |
|---------------------|------------------|------------------|

像这样设计你的表格，这样你就不必为每个子元素做表格，你可以在里面上到任何级别。

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nwlqm0z12#

您需要循环查询结果并打印类似的内容。我已经用破折号来缩进，但是你可以用html来做的更干净。我为任何想帮忙的人做了一把小提琴。https://www.db-fiddle.com/f/sbtyqbnemcem5vx3xwuuaj/0#&togetherjs=wkjd3lwafs

<?php 
$cat = $getData->get_menu_categories(); 
$lastmain = '';
$lastsub = '';
$lastsubsub = '';

foreach ($cat as $line) {
   $main = $line['main_menu_name'];
   $sub = $line['sub_menu_name'];
   $subsub = $line['sub_sub_menu_name'];

   if ($lastmain <> $main) {
       print "$main\n";
       $lastmain = $main;
   }

   if ($lastsub <> $sub) {
       print "---$sub\n";
       $lastsub = $sub;
   }

   if ($lastsubsub <> $subsub) {
       print "------$subsub\n";
       $lastsubsub = $subsub;
   }
}

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xkrw2x1b3#

<ul>
    <li>
        <ul class="nav__list">

<?php
// $cat = $getData->get_menu_categories(); // put your SQL request to the database here
$lastmain = '';
$lastsub = '';
$lastsubsub = '';
$mainx=1;
$mainy=0;
$subx=0;
$suby=0;
$subsubx=0;
$subsuby=0;
$startmainx = 0;
?>
<nav class="nav" role="navigation">
  <ul class="nav__list">
<?php
foreach ($cat as $line) {
   $main = $line['main_menu_name'];
   $sub = $line['sub_menu_name'];
   $subsub = $line['sub_sub_menu_name'];

   $mainid = $line['main_menu_id'];
   $subid = $line['sub_menu_id'];
   $subsubid = $line['sub_sub_menu_id'];

   if ($lastmain <> $main) {
        if($mainx <> $mainy){
            if($startmainx == 0){
                $mainx = $mainy;
                $startmainx =1;
            }else{
                print '</ul></li></ul></li>';//beginning
                $mainx = $mainy;
            }
        }
       echo '<li>
       <input id="group-'.$subid.'" type="checkbox" hidden />
       <label for="group-'.$subid.'">'.$main.'&nbsp; <span class="fa fa-angle-right"></span></label>';
        if(($mainx == $mainy) && ($lastmain == '')){
            echo '<ul class="group-list">';
            $mainx++;
        }
       $lastmain = $main;
        if(($mainx == $mainy) && ($lastmain == $main)){
            echo '<ul class="group-list"><li>'; //end
            $lastsub = '';
            $mainx++;
        }
   }//end 1st menu 
   if ($lastsub <> $sub) {
    if(($subx <> $suby) && ($lastsub == '')){
        $suby++;
    }
    if($subx <> $suby){
        print "</ul>";
        $suby++;
    }
       echo '<input id="sub-group-'.$subsubid.'" type="checkbox" hidden />
       <label for="sub-group-'.$subsubid.'">'.$sub.'&nbsp; <span class="fa fa-angle-right"></span></label>';
        $lastsub = $sub;
        if($subx == $suby){
                echo '<ul class="sub-group-list">';
            $subx++;
        }
   }//End 2nd menu
   if ($lastsubsub <> $subsub) {
        if($subsubx <> $subsuby){
            $subsubx =$subsuby;
        }
       echo '<li><a href="'.$subsubid.'">'.$subsub.'</a></li>';
        $lastsubsub = $subsub;
        if($subsubx == $subsuby){
           $subsubx = $subsuby;
        }
   }
}
?>

我想向大家展示我是如何根据mankowitz的答案将html添加到这个应用程序中的。

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php实现多级菜单？

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