我在js中有一个计时器脚本,我想从mysql数据库中获取数据,但不起作用,下面是我目前所做的。。
我的日期格式来自 expirydate
db是数字:“1527886800”
PHP:
<?php
$db = mysqli_connect("localhost","root","pass","db");
if (!$db) {
die ('Can\'t use db: ' . mysqli_error());
}
$qt = mysqli_query($db,"SELECT expirydate FROM licenses ");
while ($row = mysqli_fetch_assoc($qt)) {
$expire = $row['expirydate'];
$expire = strtotime( $expire );
$mysqldate = date( 'Y-m-d H:i:s', $expire );
}
?>
js公司:
<script>
function makeTimer() {
var endTime = new Date($mysqldate);
endTime = (Date.parse(endTime) / 1000);
var now = new Date();
now = (Date.parse(now) / 1000);
var timeLeft = endTime - now;
var days = Math.floor(timeLeft / 86400);
var hours = Math.floor((timeLeft - (days * 86400)) / 3600);
var minutes = Math.floor((timeLeft - (days * 86400) - (hours * 3600)) / 60);
var seconds = Math.floor((timeLeft - (days * 86400) - (hours * 3600) - (minutes * 60)));
if (hours < "10") { hours = "0" + hours; }
if (minutes < "10") { minutes = "0" + minutes; }
if (seconds < "10") { seconds = "0" + seconds; }
$(".days").html(days + "<span> Zile</span>");
$(".hours").html(hours + "<span> Ore</span>");
$(".minutes").html(minutes + "<span> Minute</span>");
$(".seconds").html(seconds + "<span> Secunde</span>");
}
setInterval(function () { makeTimer(); }, 1000);
</script>
1条答案
按热度按时间pw136qt21#
不能在js代码中直接使用php变量。你需要做一些类似的事情: