我正在尝试使用mysqli\u query在mysql表中插入php变量,其中表名也是一个变量。我尝试了stackoverflow的多种解决方案,但仍然不起作用。
我试着这样做,也许我错过了什么。提前谢谢!
<?php
session_start();
@include_once "modules/connections/dbconn.php";
$value = $_POST['value'];
$playerid = $_SESSION["steamid"];
$playername = fetchinfo("name","users","steamid",$playerid);
$playeravatar = fetchinfo("avatar","users","steamid",$playerid);
$playercoins = fetchinfo("coins", "users","steamid",$playerid);
if($playercoins - $value < 0){
die(json_encode(array('message' => 'ERROR', 'code' => "Not enough coins!")));
}
$game = fetchinfo("value","parameters","name","raffleRound");
$maxitems = fetchinfo("value","parameters","name","raffleMaxritems");
$items = fetchinfo("itemsnum","rafflegames","id",$game);
$itemname = "Coins";
$itemavatar = "images/creditcardicon.png";
$color = "D2D2D2";
$initialvalue = fetchinfo("value","rafflegames","id",$game);
$from = $initialvalue * 100;
$to = $from + $value * 100;
$tablename = 'rafflegame'.$game;
if($items < $maxitems){
mysqli_query($GLOBALS["connect"], "UPDATE rafflegames SET `value`=`value`+$value, `itemsnum`=`itemsnum`+1 WHERE `id`=$game");
mysqli_query($GLOBALS["connect"], "UPDATE users SET `coins`=`coins`-$value WHERE `steamid`=$playerid");
mysqli_query($GLOBALS["connect"], "INSERT INTO `" . $tablename . "` VALUES ('".$playerid."', '".$playername."','".$itemname."','".$color."','".$value."','".$playeravatar."','".$itemavatar."','".$from."','".$to."')");
}
else {
die(json_encode(array('message' => 'ERROR', 'code' => "Too many items in the current game")));
}
?>
另外两个查询工作正常。
表格结构如下:
mysqli_query($GLOBALS['connect'],"CREATE TABLE `rafflegame$roundNumber` (
`id` int(11) NOT NULL auto_increment,
`userid` varchar(70) NOT NULL,
`username` varchar(70) NOT NULL,
`item` text,
`color` text,
`value` float,
`avatar` varchar(512) NOT NULL,
`image` text NOT NULL,
`from` int NOT NULL,
`to` int NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=1 DEFAULT CHARSET=utf8 AUTO_INCREMENT=1;");
mysqli_query($GLOBALS['connect'],"TRUNCATE TABLE `rafflegame$roundNumber`");
1条答案
按热度按时间gwo2fgha1#
表结构和insert column coumnt之间有区别,当您希望id column自动递增时,在这种情况下,应该在insert查询中包含列名。
请使用以下代码: