我被mysql问题困住了。我试图使用以下公式计算投资组合的收益率系列:
for(i = startdate+1; i <= enddate; i++) {
return[i]=0;
for(n = 0; n < count(instruments); n++) {
return[i] += price[i,n] / price[i-1, n] * weight[n];
}
}
因此,今天投资组合的回报率计算为今天的价格/昨天的价格*投资组合中工具的权重之和。
我写了一篇潦草的文章http://rextester.com/fuc35243.
如果不起作用,代码是:
DROP TABLE IF EXISTS x_ports;
DROP TABLE IF EXISTS x_weights;
DROP TABLE IF EXISTS x_prices;
CREATE TABLE IF NOT EXISTS x_ports (id INT NOT NULL AUTO_INCREMENT, name VARCHAR(20), PRIMARY KEY (id));
CREATE TABLE IF NOT EXISTS x_weights (id INT NOT NULL AUTO_INCREMENT, port_id INT, inst_id INT, weight DOUBLE, PRIMARY KEY (id));
CREATE TABLE IF NOT EXISTS x_prices (id INT NOT NULL AUTO_INCREMENT, inst_id INT, trade_date DATE, price DOUBLE, PRIMARY KEY (id));
INSERT INTO x_ports (name) VALUES ('PORT A');
INSERT INTO x_ports (name) VALUES ('PORT B');
INSERT INTO x_weights (port_id, inst_id, weight) VALUES (1, 1, 20.0);
INSERT INTO x_weights (port_id, inst_id, weight) VALUES (1, 2, 80.0);
INSERT INTO x_weights (port_id, inst_id, weight) VALUES (2, 1, 100.0);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (1, '2018-01-01', 1.12);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (1, '2018-01-02', 1.13);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (1, '2018-01-03', 1.12);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (1, '2018-01-04', 1.12);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (1, '2018-01-05', 1.13);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (1, '2018-01-06', 1.14);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (2, '2018-01-01', 50.23);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (2, '2018-01-02', 50.45);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (2, '2018-01-03', 50.30);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (2, '2018-01-04', 50.29);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (2, '2018-01-05', 50.40);
INSERT INTO x_prices (inst_id, trade_date, price) VALUES (2, '2018-01-06', 50.66);
# GETTING THE DATES
SET @DtShort='2018-01-01';
SET @DtLong=@DtShort;
SELECT
@DtShort:=@DtLong as date_prev,
@DtLong:=dt.trade_date as date_curent
FROM
(SELECT DISTINCT trade_date FROM x_prices ORDER BY trade_date) dt;
# GETTING RETURN FOR SINGLE DAY
SET @DtToday='2018-01-03';
SET @DtYesterday='2018-01-02';
SELECT
x2.trade_date,
x2.portfolio,
sum(x2.val*x2.weight)/sum(x2.weight) as ret
FROM
(SELECT
x1.trade_date,
x1.portfolio,
sum(x1.weight)/2.0 as weight,
sum(x1.val_end)/sum(x1.val_start) as val,
sum(x1.val_start) as val_start,
sum(x1.val_end) as val_end
FROM
(SELECT
@DtToday as trade_date,
prt.name as portfolio,
wts.inst_id as iid,
wts.weight,
if(prc.trade_date=@DtToday,prc.price*wts.weight,0) as val_start,
if(prc.trade_date=@DtYesterday,prc.price*wts.weight,0) as val_end
FROM
x_ports prt,
x_weights wts,
x_prices prc
WHERE
wts.port_id=prt.id and
prc.inst_id=wts.inst_id and
(prc.trade_date=@DtToday or prc.trade_date=@DtYesterday)) x1
GROUP BY x1.portfolio) x2
GROUP BY x2.portfolio;
我希望能够产生这样的结果:
Date Port A Port B
--------------------------------------------
01/01/2010
02/01/2010 1.005289596 1.004379853
03/01/2010 0.995851496 0.997026759
04/01/2010 0.999840954 0.999801193
05/01/2010 1.003535565 1.002187314
06/01/2010 1.005896896 1.00515873
2018年2月1日a港的回报率应计算为1.13/1.1220/(20+80)+50.45/50.2380/(20+80)。
2018年2月1日b港的回报率应计算为50.45/50.23100/100,或可能为1.13/1.120/(0+100)+50.45/50.23100/(0+100)。
仅供参考,在上面的循环函数中,我只计算指定值(或未标度的权重),因此端口a将被计算为1.13/1.1220+50.45/50.23*80,我认为这是计算回报的关键步骤。然后将返回值除以权重之和,得到返回值。
虽然这当然可以做得更好,我可以得到日期,我可以计算一天的回报,但我就是不能把两者放在一起。
1条答案
按热度按时间bvhaajcl1#
模拟分析没有乐趣!演示
这方面的数学在我看来并不正确;因为我没有接近你的“看起来像结果”
我想能够重用curday,但由于版本较低,我不能使用一个共同的表表达式。
它的作用是:
x1生成表的联接
x2给了我们一个投资组合中工具的计数,这些工具后来在数学中使用
r生成一个uservariable,我们可以在其上分配行@rn和@rn2
curday生成一个正确排序的行号以便我们可以加入
nextday生成curday的一个副本,这样我们就可以在rn+1上加入curday到第二天
z允许我们在当天进行数学运算和分组,并为公文包名称的轴心做准备。
最外层的select允许我们透视数据,所以我们有date+2列
.