db类中,准备和执行不起作用,为什么?

hmmo2u0o  于 2021-06-20  发布在  Mysql
关注(0)|答案(0)|浏览(185)

尝试在php上设置db类,遵循youtube教程,在教程中运行良好,但在我的机器上“$this->\u query->execute()”返回false
这是我的课:

class DB {
private static $_instance = null;
private $_pdo, $_query, $_error = false, $_results, $_count = 0, $_lastInsertID = '';

private function __construct() {
    try{
        $this->_pdo = new PDO('mysql:host=127.0.0.1;dname=database','root','');
    } catch (PDOException $e) {
        die($e->getMessage());
    }
}

public static function get_instance(){
    if(!isset(self::$_instance)){
        self::$_instance = new DB();
    }
    return self::$_instance;
}

public function query($sql,$params = []){
    $this->_error = false;

    if($this->_query = $this->_pdo->prepare($sql)){
        $x = 1;
        var_dump($params);
        if(count($params)){
            foreach ($params as $param){
                $this->_query->bindValue($x,$param);
                $x++;
            }
        }

        if($this->_query->execute()){
            $this->_results = $this->_query->fetchAll(PDO::FETCH_OBJ);
            $this->_count = $this->_query->rowCount();
            $this->_lastInsertID = $this->_pdo->lastInsertId();
        }else{
            $this->_error = true;
        }
    }
    return $this;
}

下面是调用函数的php文件:

require_once 'classes/DB.php';

$db = DB::get_instance();

$contact = 
['Ewerton','Marschalk','Ewerton@hotmail.com','44444444444','5555555555555'];

 $db->query("INSERT INTO contacts (`fname`,`lname`,`email`,`cell_phone`,`home_phone`) values (?,?,?,?,?)",$contact);

为什么这样不行?

暂无答案!

目前还没有任何答案,快来回答吧!

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