我要将以下sql查询传递给laravel：

SELECT total.candidate_name, total.name, total.questions, COUNT(total.grade)
FROM 
(
    SELECT c.name as candidate_name, j.name, t.questions, g.grade 
    FROM candidates as c 
        INNER JOIN job_openings as j on c.fk_id_job_opening=j.id_job_opening 
        INNER JOIN interview_templates as t on  j.fk_id_template=t.id_template 
        INNER JOIN responses as r on r.fk_id_candidate=c.id_candidate 
        INNER JOIN grades as g on r.id_response=g.fk_id_response 
    WHERE g.fk_id_user='some_id'
) as total
GROUP BY total.candidate_name, total.name, total.questions;
``` `some_id` 将由接收 `Auth::id()` 方法，到目前为止，我有一个子查询工作得很好：

$subquery = Candidate::select('candidates.name AS c_name', 'j.name AS j_name', 't.questions AS questions', 'g.grade AS grade')
->join('job_openings AS j', 'candidates.fk_id_job_opening', '=', 'j.id_job_opening')
->join('interview_templates AS t', 'j.fk_id_template', '=', 't.id_template')
->join('responses AS r', 'r.fk_id_candidate', '=', 'candidates.id_candidate')
->join('grades AS g', 'r.id_response', '=', 'g.fk_id_response')
->where('g.fk_id_user',Auth::id())
->get();

但是我在语法方面遇到了问题，我对laravel还很陌生，所以这可能不是一个好的查询方法。
非常感谢你的帮助。