我有以下实体,
@Entity
@Table(name = "person")
public class Person implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
// Other fields
}
@Entity
@Table(name = "agreement")
public class Agreement implements Serializable {
private static final long serialVersionUID = 15L;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@ManyToOne
@JoinColumn(name = "person_id", nullable = false)
private Person person;
@ManyToOne
@JoinColumn(name = "company_id", nullable = false)
private Company company;
}
@Entity
@Table(name = "company")
public class Company implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;
@Column(name = "name", length = 100)
private String name;
}
我需要找所有和公司有协议的人,公司id是45。下面是我为获取详细信息而编写的本机查询。
SELECT distinct p.* ROM person p INNER JOIN agreement a ON a.person_id = p.id where a.company_id = 45;
但我被告知要将其转换为jpa实体查询。我想到了下面这个,
SELECT distinct p FROM Person p INNER JOIN Agreement a WHERE a.person = p AND a.company.id = 45;
但这给了我一个例外,
原因:org.hibernate.hql.internal.ast.querysyntaxception:应为join的路径[在org.hibernate.hql.internal.ast.querysyntaxception.convert(querysyntaxception)中选择distinct p from person p inner join agreement a,其中a.person=p和a.company.id=45]。java:74)在org.hibernate.hql.internal.ast.errorcounter.throwqueryexception(errorcounter。java:91)在org.hibernate.hql.internal.ast.querytranslatorimpl.analyze(querytranslatorimpl。java:268)在org.hibernate.hql.internal.ast.querytranslatorimpl.docomFile(querytranslatorimpl。java:190)在org.hibernate.hql.internal.ast.querytranslatorimpl.compile(querytranslatorimpl。java:142)在org.hibernate.engine.query.spi.hqlqueryplan。java:115)在org.hibernate.engine.query.spi.hqlqueryplan.(hqlqueryplan。java:76)在org.hibernate.engine.query.spi.queryplanche.gethqlqueryplan(queryplanche。java:150)在org.hibernate.internal.abstractsessionimpl.gethqlqueryplan(abstractsessionimpl。java:302)在org.hibernate.internal.abstractsessionimpl.createquery(abstractsessionimpl。java:240)在org.hibernate.internal.sessionimpl.createquery(sessionimpl。java:1894)在org.hibernate.jpa.spi.abstractentitymanagerimpl.createquery(abstractentitymanagerimpl。java:305
有人能帮我找出我在询问中做错了什么吗?
1条答案
按热度按时间b5lpy0ml1#
jpa在hql语句中使用路径来关联从一个实体到另一个实体,因为它没有找到它所抱怨的任何实体。你可以试试下面的查询。