来自多表codeigniter的结果数据

avwztpqn  于 2021-06-20  发布在  Mysql
关注(0)|答案(1)|浏览(351)

型号:

public function show_data_by_tid_pic($postid,$postpic) {
$condtid = "otslm.tid =" . "'" . $postid . "'";
$condpic = "pic.nama =" . "'" . $postpic . "'";
$this->db->select('otslm.*');
$this->db->select('pic.*');
$this->db->from('otslm');
$this->db->join('pic', 'pic.id = otslm.id');
$this->db->where($condtid);
$this->db->where($condpic);
$query = $this->db->get();
if ($query->num_rows() > 0) {
return $query->result(); } else {
return false;
}
}

控制器:

public function inputslm() {
    $postid = $this->input->post('nametid');
    $postpic = $this->input->post('namepic');
    if ($postid != "" OR $postpic != "") {
    $resultid = $this->skejuler_model->show_data_by_tid_pic($postid,$postpic);
    if ($resultid != false) {
    $data['result_display'] = $resultid;
    }
    else {
    $data['result_display'] = "Not Found!";
    }
    }
    else {
    $data = array(
    'tid_error_message' => "TID tidak boleh kosong!",
    'pic_error_message' => "PIC tidak boleh kosong!"
    );
    }
    $data['show_table'] = $this->view_table();
    $this->load->view('front/dashboard', $data);
    }

查看:

if (isset($result_display)) {
            if ($result_display == 'Not Found!') {
            echo $result_display;
            } else {
                foreach ($result_display as $vid) {
                $zlokasi = $vid->lokasi;
            $znama = $vid->nama;
            $znohp = $vid->nohp;
                }
      echo $zlokasi;
      echo "<br>";
      echo $znama;
      echo "<br>";
      echo $znohp;
            }
            }

提交后:

我是codeigniter的新手,尝试通过将表与两个字段“nametid”和“namepic”连接来生成数据。我认为代码没有错,存在列,但它总是变成假的(找不到!)。请帮我弄清楚。。。非常感谢你。。。
使用heidisql(找到行:0),联接表因where子句而失败。图1
使用heidisql(找到行:31),在没有where子句的情况下连接表success。图2

fruv7luv

fruv7luv1#

获取数据现在成功,不使用联接,将查询替换为:

$this->db->select('*');
$this->db->from('otslm');
$this->db->from('pic');
$this->db->where('tid', $postid);
$this->db->where('nama', $postpic);

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