我正在构建一个应用程序,该应用程序的一部分是允许人们喜欢某些项目。他们只需单击svg的heart图标,它就会变成红色,并以状态存储到“favorites”中,然后发送到数据库(mysql)。如果他们再次单击图标,它会变回灰色,将其从状态中删除,并运行另一个数据库获取来删除该项。
我一直在尝试将它构建到我的action creator中,但是我不能让它们都工作(也就是说,我不能让它发送到state和数据库)。不过,我确实让它在国家片中发挥了完美的作用。我把它放在下面:
export const toggleFavorite = name => (dispatch, getState) => {
const { searchResults, favorites } = getState()
const currentSelection = filter(
selection => selection.name === name,
searchResults
)
const newFavorite = contains(currentSelection, favorites)
? reject(equals(currentSelection), favorites)
: append(currentSelection, favorites)
dispatch({
type: SET_FAVORITE,
payload: newFavorite
})
}
所以,我的问题是:在哪里以及如何将回迁放在后端以允许插入和删除?这是我最后一次失败的尝试:
export const toggleFavorite = name => async (dispatch, getState) => {
const { searchResults, favorites } = getState()
const currentSelection = filter(
selection => selection.name === name,
searchResults
)
const newFavorite = contains(currentSelection, favorites)
? reject(equals(currentSelection), favorites)
await fetch(`http://localhost:5000/deletefavorite?user_id=1&selection_id=${currentSelection}`)
: append(currentSelection, favorites)
await fetch(`http://localhost:5000/addfavorite?user_id=1&selection_id=${currentSelection}`)
dispatch({
type: SET_FAVORITE,
payload: newFavorite
})
}
提前谢谢!
1条答案
按热度按时间ndh0cuux1#
应使用经典if/else替换三元条件: