sequelize多表或语句未知列错误

b1zrtrql  于 2021-06-21  发布在  Mysql
关注(0)|答案(1)|浏览(315)

我正在尝试对我的模型进行搜索,我希望得到所有用户,其中email、firstname或lastname类似于搜索字符串,或者userssecondaryemails表(相关模型)包含类似于该字符串的电子邮件。
因为or语句的部分在不同的表中,所以这有点棘手,我只能找到其他stackoverflow答案来帮助我。
以下是我的问题(简化):

const companiesUsersParams = {
  where: {
    companyId: req.params.companyId,
    roleId: role.id
  },
  include: [{
    model: models.Users,
    attributes: ['id', 'firstName', 'lastName', 'email'],
    where: req.query.s ? {
      [Op.or]: [{
        firstName: {
          [Op.like]: `%${req.query.s}%`
        }
      }, {
        lastName: {
          [Op.like]: `%${req.query.s}%`
        }
      }, {
        email: {
          [Op.like]: `%${req.query.s}%`
        }
      }, {
        '$usersSecondaryEmails.email$': {
          [Op.like]: `%${req.query.s}%`
        }
      }]
    } : null,
    include: [{
      model: models.UsersSecondaryEmails,
      attributes: ['id', 'email'],
      as: 'usersSecondaryEmails'
    }]
  }]
}

什么时候 req.query.s 没有定义,查询按预期运行(没有或语句),所以我知道这不是我的关联的问题。
当我运行此查询时 req.query.s 我明白了
“on子句”中的未知列“userssecondaryemails.email”
下面是正在生成的sql(格式尽可能好):

SELECT `companiesUsers`.`id`,
       `companiesUsers`.`company_id` AS `companyId`, 
       `companiesUsers`.`user_id` AS `userId`,
       `companiesUsers`.`role_id` AS `roleId`,
       `companiesUsers`.`created_at` AS `createdAt`, 
       `companiesUsers`.`updated_at` AS`updatedAt`,
       `user`.`id` AS `user.id`,
       `user`.`first_name` AS `user.firstName`,
       `user`.`last_name` AS `user.lastName`,
       `user`.`email` AS `user.email`,
       `user->usersSecondaryEmails`.`id` AS `user.usersSecondaryEmails.id`,
       `user->usersSecondaryEmails`.`email` AS
       `user.usersSecondaryEmails.email` 
 FROM `CompaniesUsers` AS `companiesUsers`
 INNER JOIN `Users` AS `user`
       ON `companiesUsers`.`user_id` = `user`.`id` AND 
       (`user`.`first_name` LIKE '%bob%' OR
       `user`.`last_name` LIKE '%bob%' OR
       `user`.`email` LIKE '%bob%' OR
       `usersSecondaryEmails`.`email` LIKE '%bob%')
 LEFT OUTER JOIN `UsersSecondaryEmails` AS `user->usersSecondaryEmails`
       ON `user`.`id` = `user->usersSecondaryEmails`.`user_id`
 WHERE `companiesUsers`.`company_id` = '1'
       AND `companiesUsers`.`role_id` = 20;

任何关于多表文档或sequelize中语句的建议或链接都会很好(我在文档中找不到任何这样高级的东西)。

qij5mzcb

qij5mzcb1#

我不知道如何修改的续集代码 companiesUsersParams ,但您的最终查询应该如下所示,以获得所需的输出。这可能会帮助您重写续集代码。
用户的左连接而不是内部连接。
你应该移到最后或最后一个选项 usersSecondaryEmails.email LIKE '%bob%' 到userssecondaryemails连接条件
在where子句中,检查条件(userid的user表或userssecondaryemails中至少应存在一行) SELECT companiesUsers.id, companiesUsers.company_id AS companyId, companiesUsers.user_id AS userId, companiesUsers.role_id AS roleId, companiesUsers.created_at AS createdAt, companiesUsers.updated_at ASupdatedAt, user.id AS user.id, user.first_name AS user.firstName, user.last_name AS user.lastName, user.email AS user.email, user->usersSecondaryEmails.id AS user.usersSecondaryEmails.id, user->usersSecondaryEmails.email AS user.usersSecondaryEmails.email FROM CompaniesUsers AS companiesUsers LEFT OUTER JOIN Users AS user ---- #1 ON companiesUsers.user_id = user.id AND (user.first_name LIKE '%bob%' OR user.last_name LIKE '%bob%' OR user.email LIKE '%bob%' OR) LEFT OUTER JOIN UsersSecondaryEmails AS user->usersSecondaryEmails ON companiesUsers.user_id = user->usersSecondaryEmails.user_id AND user->usersSecondaryEmails.email LIKE '%bob%' ---- #2 WHERE companiesUsers.company_id = '1' AND companiesUsers.role_id = 20 AND (user.email is Not null OR user->usersSecondaryEmails.user_id is Not Null); ---- #3

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