我使用的是django1.9.5和python2.7。我也使用mysql作为数据库。当我尝试进行迁移时,我得到以下错误
“无法添加外键约束”
当我试图将多对多字段添加到现有表中时,出现此错误。在进行迁移和迁移时,会创建多对多关系表,但没有外键约束。
同时runserver也表示;
“您有未应用的迁移;在应用程序之前,您的应用程序可能无法正常工作。“
运行“python manage.py migrate”应用它们。我可以通过网站向该表添加新数据,但不受外键约束。但是我需要用foreignkey约束为关系创建表字段。该操作将在worker和workerduty表之间创建多对多关系。mysql是innodb配置的。
错误日志:
# python manage.py migrate
Operations to perform:
Apply all migrations: authtoken, sessions, admin, auth, reversion, contenttypes, company
Running migrations:
Rendering model states... DONE
Applying company.0005_Worker_duty_type...Traceback (most recent call last):
File "manage.py", line 10, in <module>
execute_from_command_line(sys.argv)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/core/management/__init__.py", line 353, in execute_from_command_line
utility.execute()
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/core/management/__init__.py", line 345, in execute
self.fetch_command(subcommand).run_from_argv(self.argv)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/core/management/base.py", line 348, in run_from_argv
self.execute(*args,**cmd_options)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/core/management/base.py", line 399, in execute
output = self.handle(*args,**options)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/core/management/commands/migrate.py", line 200, in handle
executor.migrate(targets, plan, fake=fake, fake_initial=fake_initial)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/migrations/executor.py", line 92, in migrate
self._migrate_all_forwards(plan, full_plan, fake=fake, fake_initial=fake_initial)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/migrations/executor.py", line 121, in _migrate_all_forwards
state = self.apply_migration(state, migration, fake=fake, fake_initial=fake_initial)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/migrations/executor.py", line 198, in apply_migration
state = migration.apply(state, schema_editor)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/backends/base/schema.py", line 90, in __exit__
self.execute(sql)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/backends/base/schema.py", line 110, in execute
cursor.execute(sql, params)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/backends/utils.py", line 79, in execute
return super(CursorDebugWrapper, self).execute(sql, params)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/backends/utils.py", line 64, in execute
return self.cursor.execute(sql, params)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/utils.py", line 95, in __exit__
six.reraise(dj_exc_type, dj_exc_value, traceback)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/backends/utils.py", line 64, in execute
return self.cursor.execute(sql, params)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 112, in execute
return self.cursor.execute(query, args)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/MySQLdb/cursors.py", line 205, in execute
self.errorhandler(self, exc, value)
File "/home/dataproj/Env/dataproj/lib/python2.7/site-packages/MySQLdb/connections.py", line 36, in defaulterrorhandler
raise errorclass, errorvalue
django.db.utils.IntegrityError: (1215, 'Cannot add foreign key constraint')
代码如下:
models.py :
class Workerduty(BaseModel):
name = models.CharField(max_length=50, unique=True, verbose_name=_("Worker Duty"))
def __unicode__(self):
return self.name
class Meta:
ordering = ['name']
class Worker(BaseModel):
duty_type = models.ManyToManyField(Workerduty, verbose_name=_("Worker Duty"))
name = models.CharField(max_length=100, db_index=True, verbose_name=_("Name"))
class Meta:
permissions = (
("Workerl", _("Workerl")),
)
ordering = ['name']
def __unicode__(self):
return "%s %s" % (self.name)
def save(self, *args,**kwargs):
self.name = self.name.title()
grps = []
for Workerduty_obj in self.Workerduty.all():
grp = Group.objects.get_or_create(name=Workerduty_obj.name)[0]
grps.append(grp)
self.user.grps = grps
self.user.save()
super(Worker, self).save(*args,**kwargs)
迁移文件:
# -*- coding: utf-8 -*-
# Generated by Django 1.9.5 on 2018-06-28 20:09
from __future__ import unicode_literals
from django.db import migrations, models
import uuid
class Migration(migrations.Migration):
dependencies = [
('company', '0001_initial'),
]
operations = [
migrations.CreateModel(
name='Workerduty',
fields=[
('uuid', models.UUIDField(default=uuid.uuid4, primary_key=True, serialize=False, verbose_name='Unique Identifier')),
('name', models.CharField(max_length=50, unique=True, verbose_name='Worker Duty')),
],
options={
'ordering': ['name'],
},
),
migrations.AddField(
model_name='worker',
name='worker_type',
field=models.ManyToManyField(to='college.Workerduty', verbose_name='Worker Duty'),
),
]
1条答案
按热度按时间zwghvu4y1#
解决方案:我在做一个现有的项目。mysql数据库是utf8整理的。我用一个新的mysql准备了一个测试环境,并克隆了db。但是默认的mysql排序规则是latin1,而导入的db是utf8。因此,django在旧表和新创建的表之间存在冲突。所以我将新的mysql安装的排序规则改为utf8。因此,新创建的表现在使用新的默认utf8排序规则创建,这与导入的db相同。
我在mysql控制台上使用了以下命令: